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2 years ago

Please help, show me how to check the answer to this

Mathematics

1 answer:

sveta [45]2 years ago

5 0

3x-7=5x=19
3x-7-5x=5x+19-5x
-2x-7=19
-2x-7+7=19+7
-2x=26
-2x/-2=26/-2
x=-13

:) Did you get that?

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What is 624 divide by 27

mihalych1998 [28]

624/27

first you have to know what number that can be subtracted by 62

1. do 27 times 2 equal 54 then you subtract 62 by 54 equal 8 then you put 84 together that will 84 then multiply 27 times 3 = 81 then subtracted by 84

84-81 equal 3

In the calculator the answer is 23.1111111111

3 0

2 years ago

Hello, may someone plz help me

fenix001 [56]

Answer:

Step-by-step explanation:

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2 years ago

Write the circumference of a circle with a diameter of 49 inches in terms of pi

AleksAgata [21]

Answer:

153.94

Step-by-step explanation:

c=2r*r

The radius is half of the diameter.

To find the radius you will divide 49 inches by 2.

You should get a total of 24.5

Now that you have your radius you are going to use the circumference formula to solve.

C= 2r*r

C=2(24.5)*(24.5)

type that into the calculator (without the parenthesis) and boom your done!

You answer should be 153.938

then you round to get a total of 153.94

I hope i was able to help!

5 0

2 years ago

Read 2 more answers

PLZ HELP ME ☻ <img src="https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7Bxy%7D%7Bx%20%2B%20y%7D%20%3D%201%2C%20%5Cquad%20%5Cfrac%7Bxz%7D%

Yanka [14]

Answer:

$x=\frac{12}{7} \\y=\frac{12}{5} \\z=-12$

Step-by-step explanation:

Let's re-write the equations in order to get the variables as separated in independent terms as possible \:

First equation:

$\frac{xy}{x+y} =1\\xy=x+y\\1=\frac{x+y}{xy} \\1=\frac{1}{y} +\frac{1}{x}$

Second equation:

$\frac{xz}{x+z} =2\\xz=2\,(x+z)\\\frac{1}{2} =\frac{x+z}{xz} \\\frac{1}{2} =\frac{1}{z} +\frac{1}{x}$

Third equation:

$\frac{yz}{y+z} =3\\yz=3\,(y+z)\\\frac{1}{3} =\frac{y+z}{yz} \\\frac{1}{3}=\frac{1}{z} +\frac{1}{y}$

Now let's subtract term by term the reduced equation 3 from the reduced equation 1 in order to eliminate the term that contains "y":

$1=\frac{1}{y} +\frac{1}{x} \\-\\\frac{1}{3} =\frac{1}{z} +\frac{1}{y}\\\frac{2}{3} =\frac{1}{x} -\frac{1}{z}$

Combine this last expression term by term with the reduced equation 2, and solve for "x" :

$\frac{2}{3} =\frac{1}{x} -\frac{1}{z} \\+\\\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\ \\\frac{7}{6} =\frac{2}{x}\\ \\x=\frac{12}{7}$

Now we use this value for "x" back in equation 1 to solve for "y":

$1=\frac{1}{y} +\frac{1}{x} \\1=\frac{1}{y} +\frac{7}{12}\\1-\frac{7}{12}=\frac{1}{y} \\ \\\frac{1}{y} =\frac{5}{12} \\y=\frac{12}{5}$

And finally we solve for the third unknown "z":

$\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\\\\frac{1}{2} =\frac{1}{z} +\frac{7}{12} \\\\\frac{1}{z} =\frac{1}{2}-\frac{7}{12} \\\\\frac{1}{z} =-\frac{1}{12}\\z=-12$

8 0

2 years ago

P(-3,6), Q(-3,-6) and R(6,-2) are the vertices of a triangle. Calculate the perimeter of this triangle.

Eva8 [605]

Answer:

33.89

Step-by-step explanation:

the side lengths are the distances between the corner points of the triangle.

P and Q have the same x value, and they therefore create a side parallel to the y-axis. and it is easy to find the length of this side : it is just the difference of the y values.

PQ = 6 - (-6) = 6 + 6 = 12

QR and RP are trickier.

we need Pythagoras to calculate the length of the direct connection between these points as the Hypotenuse of the right triangles with the differences in x and in y values as the other sides.

QR :

QR² = (-3 - 6)² + (-6 - -2)² = (-9)² + (-4)² = 81 + 16 = 97

QR = sqrt(97) ≈ 9.848857802

RP :

RP² = (6 - -3)² + (-2 - 6)² = 9² + (-8)² = 81 + 64 = 145

RP = sqrt(145) ≈ 12.04159458

the perimeter/circumference of the triangle is the sum of all 3 sides

= 12 + sqrt(97) + sqrt(145) ≈ 33.89

3 0

2 years ago