6x2 + 12x + 2 = -10 Quadratic equation solve
1 answer:
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The picture in the attached figure
we know that
m∠A+m∠B+m∠C=180°-----> by the sum of the internal angles of the triangle is 180 degrees
m∠A=25°
for m∠B=51°
find ∠C
∠C=180-[25+51]---------> m∠C=104°
for m∠B greater than 51°-------> m∠C must be less than 104°
for m∠B=57°
find m∠C
m∠C=180-[25+57]---------> m∠C=98°
for m∠B less than 57°-------> m∠C must be greater than 98°
therefore
98° < m∠C < 104°
we know that
m∠A+m∠B+m∠C=180°-----> by the sum of the internal angles of the triangle is 180 degrees
m∠A=25°
for m∠B=51°
find ∠C
∠C=180-[25+51]---------> m∠C=104°
for m∠B greater than 51°-------> m∠C must be less than 104°
for m∠B=57°
find m∠C
m∠C=180-[25+57]---------> m∠C=98°
for m∠B less than 57°-------> m∠C must be greater than 98°
therefore
98° < m∠C < 104°
20
Step-by-step explanation:
Step 1:
Let the number be 50 and to find 40% of 50 is given interms of expression as follows
To express the percentage the following strategy is used
Eg: 40% =
∴ To express 40% of 50 is
Step 2:
On simplification the above expression we could get
= 20