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2 years ago

Hawaii 0.288% = what fraction

Mathematics

1 answer:

Sindrei [870]2 years ago

4 0

Answer:

36⁄125 or if we are talking about the lowest term it is 9 /3125

Step-by-step explanation:

Step 1: 0.288 = 288⁄1000

Step 2: Simplify 288⁄1000 = 36⁄125 Percent" or "%" means "out of 100" or "per 100",

<em>Or for the lowest term:</em>

Therefore 0.288% can be written as

0.288

100

Next, we can multiply by

in the form of

1000

to eliminate the decimal in the numerator:

1000

0.288

100

⇒

1000

0.288

1000

100

⇒

288

100000

We can now reduce the fraction as:

288

100000

⇒

3125

⇒

3125

⇒

3125

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At a baseball game, 6 hotdogs cost $27. What is the cost of 1 hotdog? How many hotdogs can you buy for $18

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Answer:

What is the cost of 1 hotdog?

Answer: $4.50

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Answer: 4

Step-by-step explanation:

If $27 can buy you 6 hot dogs, to find the cost of one, we just divide.

27 divided by 6 = 4.5 ($4.50)

So 1 hotdog costs $4.50

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18 divided by 4.5 = 4

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2 years ago

If an archer shoots an arrow straight upward with an initial velocity of 160

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Answer:

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Step-by-step explanation:

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We know that first derivative of height will be velocity

So first derivative of height

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t = 5 sec

Sp arrow will be at maximum height at t = 5 sec

So height at t = 5 sec will be

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2 years ago

What is 3/5+3/10+9/11

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Answer:

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Step-by-step explanation:

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3 years ago

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Write the equation for a 3rd degree polynomial function that has roots at x = 1–3i and x = 2. The y‑intercept is (0,10). Write a

HACTEHA [7]

Answer:

$\displaystyle P(x)=-\frac{1}{2}(x^2+2x+10)(x-2)$

Step-by-step explanation:

<u>Factored Form Of Polynomials </u>

If we know the roots of a polynomial as

$\alpha _1,\alpha _2,\alpha _3$

the polynomial can be expressed in factored form as

$a(x-\alpha _1)(x-\alpha _2)(x-\alpha _3)$

We are given two of the three roots of the polynomial:

$\alpha _1=1-3i$

$\alpha _2=2$

The other root must be the conjugate of the complex root:

$\alpha _3=1+3i$

Recall the product of two complex conjugate numbers is

$(1-3i)(1+3i)=1^2-(3i)^2=1+9=10$

The required polynomial is

$P(x)=a\left[ x-(1-3i)\right ]\left[ x-(1+3i)\right ](x-2)$

$P(x)=a(x^2+2x+10)(x-2)$

This is the factored form of the polynomial where only real numbers appear

We need to find the value of a, such as

$P(0)=10$

$P(0)=a(0^2+2(0)+10)(0-2)=10$

$-20a=10$

Thus the value of a is

$\displaystyle a=-\frac{1}{2}$

The expression of the required polynomial is

$\boxed{P(x)=-\frac{1}{2}(x^2+2x+10)(x-2)}$

5 0

2 years ago