Square ABCD and square EFGH will reflect onto themselves across 8 lines of reflection
Given that ∠B ≅ ∠C.
to prove that the sides AB = AC
This can be done by the method of contradiction.
If possible let AB
=AC
Then either AB>AC or AB<AC
Case i: If AB>AC, then by triangle axiom, Angle C > angle B.
But since angle C = angle B, we get AB cannot be greater than AC
Case ii: If AB<AC, then by triangle axiom, Angle C < angle B.
But since angle C = angle B, we get AB cannot be less than AC
Conclusion:
Since AB cannot be greater than AC nor less than AC, we have only one possibility. that is AB =AC
Hence if angle B = angle C it follows that
AB = AC, and AB ≅ AC.
0.08x+(x-200)
(0.08x)(x+-200)
(0.08x)(x)(0.08x)(-200)
= 0.08x^2-16x
Eg is half the length of ac
Answer:
The difference of the two means is not significant, so the null hypothesis must be rejected.