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mylen [45]
3 years ago
10

Mrs. Beach bought shells at a gift shop. The red shells (r) were $0.75 each, and the white shells (w) were $0.49 each. The total

cost was $4.70 for 8 shells. Later, the clerk forgot how many of each color shell he sold, so he guessed 4 red and 4 white shells. That was 8 shells, but the cost was $4.96. What advice would you give the clerk for his next guess?
Mathematics
2 answers:
spin [16.1K]3 years ago
8 0

Answer: The cost was too high. Since red shells cost more than white shells, the clerk’s next guess should be fewer red shells and more white shells. I would guess 3 red shells and 5 white shells.


Step-by-step explanation:


gladu [14]3 years ago
4 0
3 red shells equals $2.25 and 5 white shells equal 2.45. Add those together and you get $4.70.
So 3 red and 5 white shells would be the next guess.
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B) Angle 2 and Angle 3

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Angle 7 and 8 are supplementary

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3 years ago
the length of a rectangle is twice its width the perimeter is 48 cm what are the dimensions of the rectangle
inysia [295]

Answer:

The length=16cm and the width=8cm.

Step-by-step explanation:

Given that the length is twice the breadth or width of the rectangle

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5 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B5x%2F8y%7D" id="TexFormula1" title="\sqrt[4]{5x/8y}" alt="\sqrt[4]{5x/8y}" al
Furkat [3]

Answer:  \frac{\sqrt[4]{10xy^3}}{2y}

where y is positive.

The 2y in the denominator is not inside the fourth root

==================================================

Work Shown:

\sqrt[4]{\frac{5x}{8y}}\\\\\\\sqrt[4]{\frac{5x*2y^3}{8y*2y^3}}\ \ \text{.... multiply top and bottom by } 2y^3\\\\\\\sqrt[4]{\frac{10xy^3}{16y^4}}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{16y^4}} \ \ \text{ ... break up the fourth root}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{(2y)^4}} \ \ \text{ ... rewrite } 16y^4 \text{ as } (2y)^4\\\\\\\frac{\sqrt[4]{10xy^3}}{2y} \ \ \text{... where y is positive}\\\\\\

The idea is to get something of the form a^4 in the denominator. In this case, a = 2y

To be able to reach the 16y^4, your teacher gave the hint to multiply top and bottom by 2y^3

For more examples, search out "rationalizing the denominator".

Keep in mind that \sqrt[4]{(2y)^4} = 2y only works if y isn't negative.

If y could be negative, then we'd have to say \sqrt[4]{(2y)^4} = |2y|. The absolute value bars ensure the result is never negative.

Furthermore, to avoid dividing by zero, we can't have y = 0. So all of this works as long as y > 0.

3 0
3 years ago
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