Assume x is 100.
-x<1
-100 is smaller than 1.
Dividing by -1,
x>-1
100 is greater than -1
If the inequality is not changed,
100<-1
100 is less than -1 which is not true
Answer:
1-2y+y^2
Step-by-step explanation:
(1–y)^2
(1-y) * (1-y)
FOIL
first: 1*1 =1
outer: 1*-y = -y
inner: -y *1 = -y
last: -y*-y = y^2
Add together: 1+-y-y+y^2
1-2y+y^2
Angle A = 130° and Angle B = 110°
Solution:
Given ABCD is a trapezoid with ∠C = 70° and ∠D = 50°
If ABCD is a trapezoid, then AB is parallel to CD.
AD is a transversal to AB and CD and
BC is a tranversal to AB ad CD.
Sum of the interior angles on the same side are supplementary.
∠A + ∠D = 180°
⇒ ∠A + 50° = 180°
Subtract 50° on both sides to equal the expression.
⇒ ∠A = 180° – 50°
⇒ ∠A = 130°
Similary, ∠B + ∠C = 180°
⇒ ∠B + 70° = 180°
Subtract 50° on both sides to equal the expression.
⇒ ∠B = 180° – 70°
⇒ ∠B = 110°
Hence, angle A = 130° and angle B = 110°.
Answer:
I'm guessing it is 3x(9x20)=3x180=540
Step-by-step explanation:
