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3 years ago

10

Find the percent change

1 answer:

tatuchka [14]3 years ago

5 0

Answer:

THE answer is 4% because u divide

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Easy Bucks... <br>For what values of y does the binomial 3y−5 belong to the interval (−1; 1)?

kati45 [8]

3y-5 = -1

3y=4

y = 4/3

3y-5 = 1

3y = 6

y = 2

y must be between 4/3 and 2

y must be between 1 1/3 and 2

3 0

3 years ago

Read 2 more answers

31. Which equation can be used to describe the relationship between x and y shown in the graph below?

Ipatiy [6.2K]

I’m sorry I don’t see the graph so I would not know.

6 0

2 years ago

A wall in Marcu's bedroom is 8 2/5 feet high and 16 2/3 feet long. If he paint 1/2 of the wall blue, how many square feet will b

ch4aika [34]

High=42/5; long =50/3
area of this is = 42/5 ×50/3=140
half of the wall is = 140/2=70
answer is 70

8 0

3 years ago

klasskru [66]

Answer:

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$y=0,\:x=6$

Step-by-step explanation:

Considering the system of the equations

$\begin{bmatrix}2x-7y=12\\ -x+15y=-6\end{bmatrix}$

$\mathrm{Isolate}\:x\:\mathrm{for}\:2x-7y=12$

$2x-7y+7y=12+7y$

$2x=12+7y$

Divide both sides by 2

$\frac{2x}{2}=\frac{12}{2}+\frac{7y}{2}$

$x=\frac{12+7y}{2}$

$\mathrm{Subsititute\:}x=\frac{12+7y}{2}$

$\begin{bmatrix}-\frac{12+7y}{2}+15y=-6\end{bmatrix}$

$-\frac{12+7y}{2}+15y=-6$

$\mathrm{Multiply\:both\:sides\:by\:}2$

$-\frac{12+7y}{2}\cdot \:2+15y\cdot \:2=-6\cdot \:2$

$-\left(12+7y\right)+30y=-12$

$-12+23y=-12$

$-12+23y+12=-12+12$

$23y=0$

$\mathrm{Divide\:both\:sides\:by\:}23$

$\frac{23y}{23}=\frac{0}{23}$

$y=0$

$\mathrm{For\:}x=\frac{12+7y}{2}$

$\mathrm{Subsititute\:}y=0$

$x=\frac{12+7\cdot \:0}{2}$

$x=\frac{12}{2}$

$x=6$

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$y=0,\:x=6$

4 0

3 years ago

Make f the subject of the formula c=<img src="https://tex.z-dn.net/?f=%5Cfrac%7B5%28f-32%29%7D%7B9%7D" id="TexFormula1" title="\

lara31 [8.8K]

Answer:

$f=\frac{9c}{5}+32$

Step-by-step explanation:

$c=\frac{5\left(f-32\right)}{9}$

Switch sides:

$\frac{5\left(f-32\right)}{9}=c$

Multiply both sides by 9:

$\frac{9\times5\left(f-32\right)}{9}=9c$

$5\left(f-32\right)=9c$

Divide both sides by 5:

$\frac{5\left(f-32\right)}{5}=\frac{9c}{5}$

$f-32=\frac{9c}{5}$

Add 32 to both sides:

$f-32+32=\frac{9c}{5}+32$

$f=\frac{9c}{5}+32$

8 0

3 years ago