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3 years ago

What is the probability that a 51% free-throw shooter will miss her next free throw?

1 answer:

6 0

Assuming all throws are independent of each other, the probability of making the next throw is still 51%, and ... missing it is 100-51=49%

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Which expressions are equivalent to the one below? Check all that apply.

dalvyx [7]

5^3(5^x) the rule is a^b(a^c)=a^(b+c)

5^(3+x)

8 0

3 years ago

Answer the questions about the dot and box plot.

ivanzaharov [21]

Answer:

a. 104

b. 102, 104, and 105

Step-by-step explanation:

a. There are 13 data points plotted on the dot line. The median lies between the 6th and 7th data point.

Thus, on the dot line, the 6th and 7th data points both fall on 104.

Therefore, median = 104

b. The dot plot shows the high temperatures that occurred more than one day are:

102, 104, and 105

5 0

3 years ago

If you have 3x + y = 9 write it in slope intercept form... what is the slope, y intercept?

ladessa [460]

Step-by-step explanation:

given

3x + y = 9

Writing In slope intercept form , y = mx + c

y = -3x + 9

comparing the given equation with y = mx + c

slope (m) = - 3

y-intercept (c) = 9

Hope it will help :)

3 0

3 years ago

Find the value of x in the given

iren2701 [21]

Answer:

You divide 62/12=5.166

5 0

3 years ago

Help with this question Asap!! I need all the help I can get!

tankabanditka [31]

Answer:

$\large{YES}\ \dfrac{BC}{YZ}=\dfrac{AC}{XY}=\dfrac{AB}{XZ}=\dfrac{2}{1}\\\\\text{and}\ \angle B\cong\angle Z,\ \angle C\cong\angle Y,\ \angle A\cong\angle X$

Step-by-step explanation:

$BC\to ZY\\AB\to XZ\\AC\to XY\\\angle A\to\angle X\\\angle B\to\angle Z\\\angle C\to\angle Y$

$\text{We have:}\\\\\triangle ABC:\ AB=20,\ BC=12,\ AC=18\\\triangle XZY:\ XZ=10,\ YZ=6,\ XY=9\\\\\text{check the ratio:}\\\\\dfrac{AB}{XZ}=\dfrac{20}{10}=2\\\\\dfrac{BC}{YZ}=\dfrac{12}{6}=2\\\\\dfrac{AC}{XY}=\dfrac{18}{9}=2\\\\\text{CORRECT :)}\\\\\angle B\cong\angle Z,\ \angle C\cong\angle Y\\\\\text{We know that: The sum of the acute angles in a right triangle is}\ 90^o.\\\\m\angle B+m\angle A=90^o\ \text{and}\ m\angle Z+m\angle X=90^o$

$\text{We know}\ m\angle B=m\angle Z\to \ m\angle A=m\angle X.\\\text{therefore}\ \angle A\cong\angle X$

5 0

3 years ago