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Dafna11 [192]
2 years ago
10

5. Two vertices of a rectangle are (8,-5) and (8,7). If the area of the rectangle is 72 square units, name the possible location

of the other two vertices. 6. A triangle with two vertices located at (5,-8) and (5, 4) has an area of 48 square units Determine one possible​
Mathematics
1 answer:
Phantasy [73]2 years ago
4 0

Answer:

<h3>#5</h3>

<u>Given vertices:</u>

  • (8, -5) and (8, 7)

These have same x-coordinate, so when connected form a vertical segment.

<u>The length of the segment is:</u>

  • 7 - (-5) = 12 units

The area of the rectangle is 72 square units, so the horizontal segment has the length of:

  • 72/12 = 6 units

<u>Possible location of the remaining vertices (to the left from the given):</u>

  • (8 - 6, -5) = (2, -5)

and

  • (8 - 6, 7) = (2, 7)
<h3>#6</h3>

<u>Similarly to previous exercise:</u>

  • (5, -8) and (5, 4) given with the area of 48 square units

<u>The distance between the given vertices:</u>

  • 4 - (-8) = 12 units

<u>The other side length is:</u>

  • 48/12 = 4 units

<u>Possible location of the other vertices (to the right from the given):</u>

  • (5 + 4, -8) = (9, -8)

and

  • (5 + 4, 4) = (9, 4)
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The length of a rectangle is 5in longer than its width. If the perimeter of the rectangle is 46in, find its area
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<span>width = x
</span><span>length = x+5

2x + 2(x+5) = 46
2x + 2x + 10 = 46
4x = 46 - 10
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