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larisa [96]
2 years ago
12

According to the synthetic division below, which of the following statements are true? Check all that apply

Mathematics
1 answer:
slamgirl [31]2 years ago
8 0

Answer:

Step-by-step explanation:

Looking at our particular problem...let's identify everything that's going on here. What's inside the box are the coefficients from the original polynomial, with the last number being the constant. If we have 3 numbers there, which we do, then the first number is a coefficient on x², the second number is the coefficient on x, and the third number is the constant. So from that we know that our original polynomial was a 2nd degree, namely:

3x² + 7x - 20

The number outside the box is the number we are dividing into this original polynomial. This is a number in solution form. That means that x = -4. If

x = -4 is a solution, then the factor is (x + 4) = 0.

The numbers in the very bottom row are the coefficients of what is called the depressed polynomial, and this depressed polynomial is one degree less than the degree with which we started. So this depressed polynomial is a linear one (first degree, which is a line). The very last number in this bottom row is the remainder. If the remainder is 0, then -4 is a solution of the polynomial, it is also a 0, and (x + 4) is a factor of the polynomial. Our remainder is a 0.

So putting that all together gives us the answers as A, C, and E are our choices.

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2<br>If A=<br>4 3<br>find A1 using<br>elementary row operations.​
MA_775_DIABLO [31]

Answer:   A^{-1}=\left[\begin{array}{cc}\frac{3}{2}&-\frac{1}{2}\\-2&1\end{array}\right]

<u>Step-by-step explanation:</u>

                  \left[\begin{array}{cc}2&1\\4&3\end{array}\right]=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]

\dfrac{1}{2}Row\ 1\rightarrow\left[\begin{array}{cc}1&\frac{1}{2}\\4&3\end{array}\right]=\left[\begin{array}{cc}\frac{1}{2}&0\\0&1\end{array}\right]

Row\ 2 -4 \ Row\ 1\rightarrow \left[\begin{array}{cc}1&\frac{1}{2}\\0&1\end{array}\right]=\left[\begin{array}{cc}\frac{1}{2}&0\\-2&1\end{array}\right]

Row\ 1-\dfrac{1}{2}\ Row\ 2 \rightarrow \left[\begin{array}{cc}1&0\\0&1\end{array}\right]=\left[\begin{array}{cc}\frac{3}{2}&-\frac{1}{2}\\-2&1\end{array}\right]

5 0
3 years ago
How to finsd the set of numbers if the mean, median and mode is given
Bad White [126]

Answer:

a) we have the numbers 0, 2, 3, 5, 5. The mean and the median are both 3

b) we have the numbers 0, 0, 3, 5, 7. The mean and the median are both 3

In both cases the mean and the median are 3, but the mode differs. The mean and the median do not uniquely determine the mode.

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
viktor has $250 in his bano account. he withdraws $15 per week. let x represent the number of weeks that he makes withdrawals an
antiseptic1488 [7]
The answer is y=$250-$15x. 
6 0
3 years ago
Ini apa we jawabannya pelasee​
kupik [55]

Answer:

<h3></h3><h2><u>kualitas terjemahannya mungkin tidak bagus. Jadi lihat 2 baris terakhir jika Anda tidak mengerti.</u></h2>

Jadi jumlah derajat tidak masalah. Mereka masih akan menempuh jarak yang sama.

Karena Anda mengatakan bahwa ekspres Marina berjalan pada 40 km / jam dan kami melakukan 2 jam. 40 * 2 = 80 km. Untuk Dumai Anda melakukan hal yang sama, 48 * 2 = 96.

Marina berjalan sejauh 80 km

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8 0
2 years ago
If f(z)=m^z - n^z, and f(1)=2, f(2)=8. Find f(3).
Marina CMI [18]
If f(z)=m^z - n^z <span>and f(1)=2, f(2)=8
then
m -  n = 2 so m = n + 2 
m^2 - n^2 = 8

substitute </span>m = n + 2  into m^2 - n^2 = 8

so
m^2 - n^2 = 8
(n + 2)^2 - n^2 = 8
n^2 + 4n + 4 - n^2 = 8
4n = 4
  n = 1

m = n + 2 = 1 + 2 = 3

so f(z) = 3^z - 1^z

if z = 1 the f(1) = 3^1 - 1^1 = 2
if z = 2 the f(2) = 3^2 - 1^2 = 9 - 1 = 8
if z = 3 the f(3) = 3^3 - 1^2 = 27 - 1 = 26

answer
f(3) = 26

3 0
3 years ago
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