Hello,
y=2xe^x
y'=2(e^x+xe^x)=2(x+1)e^x
y''=2(e^x+(x+1)e^x)=2(x+2)e^x
x |-infinite -2 0 +infinite
e^x | ++++++++++++++++++
x+2 |------------0 +++++++++++
y'' | -----------0 +++++++++++
y''<0 if x<-2
<span>The interval on which the graph is concave down is (-infinite -2[</span>
Answer:
The value of f(g(3) = 1,008
Step-by-step explanation:
<u>Step:-1</u>
Given f(x) =
and g(x) = 3x+9
h(x) = 12+x
Given g(x) = 3x+9
put x =3
g(3) = 3(3)+9
<u> g(3) = 18</u>
<u>Step :-(2)</u>
f(g(3)) = f(18)
f(g(3) = 3(18)^2 +2(18) (since f(x) =
)
= 1,008
<u>Final answer</u>:-
The value of f(g(3) = 1,008
Answer:
B
Step-by-step explanation:
Also solved eveything
(x+9)^2=49
x^2+18x+81=49
x^2+18x+32=0
a=1, b=18 and c=32
x= (-18 +/- Sqrt (18^2-4×32))/2
x= (-18 +/- Sqrt (324-128))/2
x= (-18 +/- Sqrt (196))/2
x= (-18 +/- 14)/2
x= (-18 +14)/2 = -4/2 =-2
OR
x= (-18 -14)/2 = -32/2 =-16
Answer:
after 10 seconds the charge is 1.624
Step-by-step explanation:
I think your question missed key information, allow me to add in and hope it will fit the orginal one.
The electrical charge on a metal plate is given by the function below, where t is the time in seconds. What is the charge after 10 seconds?
C (t) = 12
My answer:
Given the information:
C (t) = 12
when t =10 we have:
C (10) = 12
<=> C (10) = 12
<=> C (10) = 12
<=> C (10) = 12 * 0.1353
<=> C (10) = 1.624
Hence, after 10 seconds the charge is 1.624