It's 192, I'm pretty sure. I hope that you get this right! :^)
Answer:
I don't understand what the question is asking please expain
If A, B and C are collinear, then
1) if B is between A and C:
AC = AB + BC
AC = 48 + 22 = 70
2) if C is between A and B:
AB = AC + BC
48 = AC + 22 |-22
AC = 26
3) if A is between B and C:
BC = AB + AC
22 = 48 + AC |-48
AC = - 26 < 0 FALSE
Answer:
if B is between A and C, then AC = 70
if C is between A and B, then AC = 26
(9/18)(9/18) = 81/324. The probability that Amy takes out pink chips in both draws is 81/324.
In this example we will use the probability property P(A∩B), which means given two independent events A and B, their joint probability P(A∩B) can be expressed as the product of the individual probabilities P(A∩B) = P(A)P(B).
The total number of chips of different colors in Amy's bag is:
8 blue chips + 9 pink chips + 1 white chip = 18 color chips
Amy takes out a chip from the bag randomly without looking, she replaces the chip and then takes out another chip from the bag.
So, the probability that Amy takes out a pink chip in the first draw is:
P(A) = 9/18 The probability of takes out a pink chip is 9/18 because there are 9 pink chips in the total of 18 color chips.
Then, Amy replaces the chip an takes out another which means there are again 18 color chips divide into 8 blue chips, 9 pink chips, and 1 white chip. So, the probability of takes out a pink chip in the second draw is:
P(B) = 9/18 The probability of takes out a pink chip is 9/18 because there are 9 pink chips in the total of 18 color chips.
What is the probability that Amy takes out a pink chip in both draws?
P(A∩B) = P(A)P(B)
P(A∩B) = (9/18)(9/18) = 81/324
Answer:
34.576 = 30 + 4 + 0.5 + 0.07 + 0.006
