The range of Ervin's scores is 55.
Range is the difference between the largest number and the smallest number.
To find the range of a set of values, first sort the values numerically (smallest to largest). With this set, it would look like this: 138, 142, 155, 165, 172, 193. Lastly, subtract 138 from 193 to find the range. By doing so, you will get 55 as an answer.
I hope this helps!
Step-by-step explanation:
H0: u = 44.3
Hi : u# 44.3
Z1-0.05/2
Z1-0.025
Z0.975 = 1.96
Z = x-u/s.d/√n
Z= 44.4 -44.3/2.6/√130
Z = (0.1×11.4018)/2.6
Z=0.44
Since the calcalculated value is less than the table value and does not fall in the rejection region we fail to reject the null hypothesis
Answer:
Step-by-step explanation:
It maybe will be ![\neq x^{2} \leq \\ \\ \int\limits^a_b {x} \, dx \int\limits^a_b {x} \, dx \sqrt{x} \\ \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right. x^{2} x^{2} \sqrt{x} \lim_{n \to \infty} a_n \lim_{n \to \infty} a_n \neq \sqrt{x} \sqrt[n]{x} \frac{x}{y} \frac{x}{y} \alpha \beta x_{123} \\ x^{2} \int\limits^a_b {x} \, dx x^{2}](https://tex.z-dn.net/?f=%5Cneq%20x%5E%7B2%7D%20%5Cleq%20%5C%5C%20%5C%5C%20%5Cint%5Climits%5Ea_b%20%7Bx%7D%20%5C%2C%20dx%20%5Cint%5Climits%5Ea_b%20%7Bx%7D%20%5C%2C%20dx%20%5Csqrt%7Bx%7D%20%5C%5C%20%5Cleft%20%5C%7B%20%7B%7By%3D2%7D%20%5Catop%20%7Bx%3D2%7D%7D%20%5Cright.%20%5Cleft%20%5C%7B%20%7B%7By%3D2%7D%20%5Catop%20%7Bx%3D2%7D%7D%20%5Cright.%20x%5E%7B2%7D%20x%5E%7B2%7D%20%5Csqrt%7Bx%7D%20%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20a_n%20%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20a_n%20%5Cneq%20%5Csqrt%7Bx%7D%20%5Csqrt%5Bn%5D%7Bx%7D%20%5Cfrac%7Bx%7D%7By%7D%20%5Cfrac%7Bx%7D%7By%7D%20%5Calpha%20%5Cbeta%20x_%7B123%7D%20%5C%5C%20x%5E%7B2%7D%20%5Cint%5Climits%5Ea_b%20%7Bx%7D%20%5C%2C%20dx%20x%5E%7B2%7D)
Answer:
216
Step-by-step explanation:
If she makes 5/6 foul throw shots, she misses 1/6;
So, if she misses 36 foul shots missed, she attempts 6 times as many;
Therefore, we just need to multiply 36 by 6:
36×6 = 216
