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2 years ago

A recipe for cake calls for 5.25 deciliters of milk. How many liters of milk are needed for the cake?

1 answer:

7 0

To convert the amount of milk from deciliters to liters we proceed as follows:
1 liter = 10 deciliters
therefore the amount of liters used in making the cake will be found as follows:
5.25/10×1=0.525 liters

Answer: 0.525 liters

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I don't know how to do this, I wasn't paying attention in class

solmaris [256]

Answer:

39.837168574084177751131265854635

Step-by-step explanation:

If you plug it into a calculator, you get that.

Next time, please pay attention in class and save us all a little trouble.

7 0

2 years ago

Simplify expression x8y-26/x14y-5 × x-39y-21

koban [17]

The simplified form of the expression is $x^{-45} y^{-42}$

<h3>Simplifying an expression</h3>

From the question, we are to simplify the given expression

The given expression is

$\frac{x^{8}y^{-26} }{x^{14}y^{-5} } \times x^{-39} y^{-21}$

The expression can be simplified as shown below

$\frac{x^{8}y^{-26} }{x^{14}y^{-5} } \times x^{-39} y^{-21}$

$\frac{x^{8} \times x^{-39} \times y^{-26} \times y^{-21} }{x^{14} \times y^{-5} }$

$\frac{x^{8+-39} \times y^{-26+-21} }{x^{14} \times y^{-5} }$

$\frac{x^{8-39} \times y^{-26-21} }{x^{14} \times y^{-5} }$

$\frac{x^{-31} \times y^{-47} }{x^{14} \times y^{-5} }$

Then,

$\frac{x^{-31} }{x^{14} } \times \frac{ y^{-47} }{ y^{-5} }$

$x^{-31-14} \times y^{-47--5}$

$x^{-31-14} \times y^{-47+5}$

$x^{-45} \times y^{-42}$

$x^{-45} y^{-42}$

Hence, the simplified form of the expression is $x^{-45} y^{-42}$

Learn more on Simplifying an expression here: brainly.com/question/2320607

#SPJ1

3 0

1 year ago

Which number does Not represent 4.701

konstantin123 [22]

Answer:

4.702 does not represent 4.701

Step-by-step explanation:

#teamtrees #WAP (Water And Plant)

6 0

2 years ago

Read 2 more answers

In the interval 0 x 360 find the values of x for which cos x =0.7252

Sergeeva-Olga [200]

Answer:

$x_1 = 43.5145\°$

$x_2 = 316.4855\°$

Step-by-step explanation:

We have a positive value for the cosine of x, so we know that the value of x should be in the first quadrant (0 ≤ x ≤ 90) or in the fourth quadrant (270 ≤ x ≤ 360).

Now, let's find the value of x that gives cos(x) = 0.7252 using the inverse function of the cosine, that is, the arc cosine function.

The value of x can be calculated using:

$x = arccos(0.7252)$

Using this function in a calculator (you may find it as: $cos^{-1}(x)$ ), we have that:

$x_1 = 43.5145\°$

So this is the value of x in the first quadrant. To find the other value of x, in the fourth quadrant, that gives the same result, we just need to calculate 360° minus the value we found:

$x_2 = 360\° - 43.5145\° = 316.4855\°$

So the values of x are:

$x_1 = 43.5145\°$

$x_2 = 316.4855\°$

7 0

2 years ago

Math Problem:

kirza4 [7]

Answer:

Her answer is not reasonable. Her average is 83.

Step-by-step explanation:

Add all of her test grades together (96+82+78+76=332)

To find the average, you need to add all test grades she got and then divide the sum by the total number of numbers added (in this case, we added 4 tests together, so we need to divide by 4)

$\frac{332}{4} =83$

So she added wrong and forgot to divide by the total number of tests.

3 0

2 years ago