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2 years ago

Can y’all help me with this plzzzz

Mathematics

2 answers:

Leviafan [203]2 years ago

6 0

Answer:

the answer is 1080 so yea

NeTakaya2 years ago

6 0

Answer:

1080

Step-by-step explanation:

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Find the formula for the nth term of the arithmetic sequence -39, 61, 161, 261, ...

maksim [4K]

<h3>Given that it is arithmetic</h3>

$d = a_{2} - a_{1} = 61 - ( - 39) = 100$

$a_{n} = a_{1} + (n - 1)d \\ a_{n} = - 39+ 100 (n - 1) \\ a_{n} = - 39 + 100n - 100 \\ a_{n} = - 139 + 100n$

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1 year ago

Decide whether this situation is looking for the part, the percent, or the whole. 14 compact cars are 56% of the cars sold tha

bekas [8.4K]

Answer:percent

Step-by-step explanation: I don’t know

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2 years ago

Read 2 more answers

A package of 24 pencils costs 2.88$. at this rate how much would 30 pencils cost?

ASHA 777 [7]

24➗2.88=0.8 30➗0.8 = 3.75 So the answer is 3.75

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2 years ago

In a company, 37‰ of the 1500 employees are female. how many are male?

Mashcka [7]

Answer:

945 males

Step-by-step explanation:

1500*37/100= 555 female

1500-555 = 945 male

Because 1500 is the total number so it is eual a 100% and you do the cross multiply. You will get 555 for female. And you use the total to subtract female employees and you will get male employees number.

7 0

2 years ago

A private and a public university are located in the same city. For the private university, 1038 alumni were surveyed and 647 sa

Snezhnost [94]

Answer:

The difference in the sample proportions is not statistically significant at 0.05 significance level.

Step-by-step explanation:

Significance level is missing, it is α=0.05

Let p(public) be the proportion of alumni of the public university who attended at least one class reunion

p(private) be the proportion of alumni of the private university who attended at least one class reunion

Hypotheses are:

$H_{0}$ : p(public) = p(private)

$H_{a}$ : p(public) ≠ p(private)

The formula for the test statistic is given as:

z= $\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}}$ where

p1 is the sample proportion of public university students who attended at least one class reunion ( $\frac{808}{1311}=0.616$ )

p2 is the sample proportion of private university students who attended at least one class reunion ( $\frac{647}{1038}=0.623$ )

p is the pool proportion of p1 and p2 ( $\frac{808+647}{1311+1038}=0.619$ )

n1 is the sample size of the alumni from public university (1311)

n2 is the sample size of the students from private university (1038)

Then z= $\frac{0.616-0.623}{\sqrt{{0.619*0.381*(\frac{1}{1311} +\frac{1}{1038}) }}}$ =-0.207

Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.

6 0

3 years ago