Answer:
\frac{13+\left(-3\right)^2+4\left(-3\right)+1-\left(-10-\left(-6\right)\right)}{\frac{\left(4+5\right)}{\left(4^2-3^2\left(4-3\right)-8\right)}+12}=5
Step-by-step explanation:
Answer:
36
Step-by-step explanation:
Area of total region = 12 ×5
=60
Area of the small region = 8×3
=24
Area of shaded region = Area of Total region - area of small region
= 60 - 24
= 36
Answer:
y = -4/3x +4
Step-by-step explanation:
y= mx+b
solve for y.
4x+3y=12
Step 1: Add -4x to both sides.
4x+3y+−4x=12+−4x
3y=−4x+12
Step 2: Divide both sides by 3.
Let's solve for y.
4x+3y=12
Step 1: Add -4x to both sides.
4x+3y+−4x=12+−4x
3y=−4x+12
Step 2: Divide both sides by 3.
3y / 3 =-4x +12 /3
y = -4/3x +4
hopes this helps you out
Answer: The proof is mentioned below.
Step-by-step explanation:
Here, Δ ABC is isosceles triangle.
Therefore, AB = BC
Prove: Δ ABO ≅ Δ ACO
In Δ ABO and Δ ACO,
∠ BAO ≅ ∠ CAO ( AO bisects ∠ BAC )
∠ AOB ≅ ∠ AOC ( AO is perpendicular to BC )
BO ≅ OC ( O is the mid point of BC)
Thus, By ASA postulate of congruence,
Δ ABO ≅ Δ ACO
Therefore, By CPCTC,
∠B ≅ ∠ C
Where ∠ B and ∠ C are the base angles of Δ ABC.
