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Iteru [2.4K]
3 years ago
6

Y-x=15 y-x=5 using elimination

Mathematics
1 answer:
Galina-37 [17]3 years ago
3 0

Answer:

No solution

Step-by-step explanation:

To eliminate is to get rid of one of the variables.

You can choose to either add each term in the equations or subtract each term in the equation.

For a variable to be eliminated, there must one pair that have the same constant with it. Each equation already has the same constant with a variable.

Try adding them.

.     y - x = 15

<u>+    y - x = 5</u>

2y - 2x = 20   No variables were eliminated.

Try subtracting.

.     y - x = 15

<u>-     y - x = 5</u>

0y - 0x  = 10   All variables were eliminated.

.         0 = 10     This is false.

This system of equations cannot be solved.

Graphically, these two lines would have the same slope and are parallel. The solution to a system is same as the point of intersection. Parallel lines never meet, never intersect, therefore there is no solution.

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QUESTION TWO Determine whether or not a constant function can be
Sveta_85 [38]
<h3>Answers:</h3>
  • (a) It is <u>never</u> one-to-one
  • (b) It is <u>never</u> onto

=========================================================

Explanation:

The graph of any constant function is a horizontal flat line. The output is the same regardless of whatever input you select. Recall that a one-to-one function must pass the horizontal line test. Horizontal lines themselves fail this test. So this is sufficient to show we don't have a one-to-one function here.

Put another way: Let f(x) be a constant function. Let's say its output is 5. So f(x) = 5 no matter what you pick for x. We can then show that f(a) = f(b) = 5 where a,b are different values. This criteria is enough to show that f(x) is not one-to-one. A one-to-one function must have f(a) = f(b) lead directly to a = b. We cannot have a,b as different values.

----------------------------

The term "onto" in math, specifically when it concerns functions, refers to the idea of the entire range being accessible. If the range is the set of all real numbers, then we consider the function be onto. There's a bit more nuance, but this is the general idea.

With constant functions, we can only reach one output value (in that example above, it was the output 5). We fall very short of the goal of reaching all real numbers in the range. Therefore, this constant function and any constant function can never be onto.

4 0
2 years ago
When x=6...................,,,.,..,.,
Zinaida [17]
It’s going to be 1/2(6^2 + 4) = 20
7 0
3 years ago
Read 2 more answers
In triangle ABC, the size of angle B is 5 times the size of angle A, and the size of angle C is 7 less than 4 times the size of
kipiarov [429]
It sounds like everything is being described in reference to angle A, so a good starting point is to pick a variable to represent the measure of angle A. I'm going to use "a" for that.

Next, I'm going to take the verbal descriptions in the problem and "translate" them into "math language". They say angle B is 5 times angle A, so that means the measure of angle B is actually 5a. The size of angle C is 5 degrees less than 4 times the size of A, so that translates to 4a-5.

We now know the following:

Angle A: a
Angle B: 5a
Angle C: 4a-5

Now, to find the value of a, we need to remember that all the angles in a triangle add up to 180 degrees.

So we have: a+5a+4a-5 = 180

We can solve that equation by combining like terms to get: 10a-5=180

We can add 5 to both sides: 10a =185

And divide by 10: a = 18.5

That tells us the measure of angle A! (It's 18.5 degrees). Now we can go back and find B by multiplying A by 5. We get 92.5 degrees for that.

Finally, we can find C by taking 4*18.5-5. We get 69 degrees for that.

One last thing-- let's check that they really do add up to 180! 69+92.5+18.5 = 180. Yep!

Hope that helps you!!
5 0
3 years ago
In ΔBCD, \overline{BD} BD is extended through point D to point E, \text{m}\angle CDE = (9x-12)^{\circ}m∠CDE=(9x−12) ∘ , \text{m}
UNO [17]

Answer:

Angle BCD is 13 degrees

Step-by-step explanation:

Here, we want to find the measure of angle BCD

To get this, we need an appropriate diagram. The diagram can be seen in the attachment.

To find the value of BCD, we can use an important triangle theorem.

This is that the sum of opposite interior angles of a triangle equals the exterior angle.

Thus, we have that;

BCD + DBC = CDE

hence;

3x + 5 + 2x + 3 = 9x-12

5x + 8 = 9x -12

9x-5x = 8 + 12

4x = 20

x = 20/4

x = 5

So the measure of BCD will be 2(5) + 3 = 10 + 3 = 13

8 0
3 years ago
I need help with this one exercise to finish so any help would be greatly appreciated!
Elodia [21]

Answer:

No Solutions

Step-by-step explanation:

for |4x -3| + 10 < 2

|4x - 3| < -8

Not possible since absolute value is positive

4 0
2 years ago
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