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KengaRu [80]
2 years ago
13

at the beginning of the day stock cuz opened at $7.25 at the end of the day it closed at $6.88 what is the rate change of stock

xyz
Mathematics
2 answers:
Sphinxa [80]2 years ago
5 0

Answer:

Correct answer for apex is -5%

Step-by-step explanation:

Vsevolod [243]2 years ago
4 0
The absolute change is the difference: 6.88 - 7.25 = -0.37

The rate of change is that divided by the originalprice x 100

Ratre of change: (-0.37/7.25 )*100 = -4.93%

You might be interested in
A lottery game has balls numbered 1 through 15. What is the probability of selecting an even numbered ball or a 13?
LiRa [457]

Answer:

8 / 15

Step-by-step explanation:

Sample space = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15}

Required outcome :

Even numbers = (2, 4, 6, 8, 10, 12, 14) or 13

Total required outcomes = 8

Probability = required outcome / Total possible outcomes

P(even number or 13) = 8 / 15

4 0
2 years ago
Write 10 1/4 as a decimal number
EastWind [94]

Answer:

10.25

Step-by-step explanation:

1/4- is 0.25

SO

we don't have to change 10 because it is a whole number.

The answer is 10.25

4 0
3 years ago
Read 2 more answers
When completing an online shopping transaction, a typical shopper takes 5 seconds to select each product and another 60 seconds
natulia [17]

4 products are being purchased.

Step-by-step explanation:

Given,

Time taken to select each product = 5 seconds

Time taken to complete check out process = 60 seconds

Total time taken for a transaction = 80 seconds

Let,

x be the number of products purchased.

Time taken for each product*Number of product + Time for check out process = total process

5x+60=80\\5x=80-60\\5x=20

Dividing both sides by 5

\frac{5x}{5}=\frac{20}{5}\\x=4

4 products are being purchased.

Keywords: variable, division

Learn more about division at:

  • brainly.com/question/11258952
  • brainly.com/question/11343416

#LearnwithBrainly

8 0
3 years ago
what fraction is equivalent to -3/2? i’m going to keep writing because it has to be 20 words. Anyways thank you if you answer th
Alinara [238K]
A fraction that is equivalent to -3/2 would be -9/6

A great form to prove this is by using a calculator and dividing -9 by 6 this should get you the answer of 1.5!

Hope this helps!
7 0
2 years ago
Let z=3+i, <br>then find<br> a. Z²<br>b. |Z| <br>c.<img src="https://tex.z-dn.net/?f=%5Csqrt%7BZ%7D" id="TexFormula1" title="\sq
zysi [14]

Given <em>z</em> = 3 + <em>i</em>, right away we can find

(a) square

<em>z</em> ² = (3 + <em>i </em>)² = 3² + 6<em>i</em> + <em>i</em> ² = 9 + 6<em>i</em> - 1 = 8 + 6<em>i</em>

(b) modulus

|<em>z</em>| = √(3² + 1²) = √(9 + 1) = √10

(d) polar form

First find the argument:

arg(<em>z</em>) = arctan(1/3)

Then

<em>z</em> = |<em>z</em>| exp(<em>i</em> arg(<em>z</em>))

<em>z</em> = √10 exp(<em>i</em> arctan(1/3))

or

<em>z</em> = √10 (cos(arctan(1/3)) + <em>i</em> sin(arctan(1/3))

(c) square root

Any complex number has 2 square roots. Using the polar form from part (d), we have

√<em>z</em> = √(√10) exp(<em>i</em> arctan(1/3) / 2)

and

√<em>z</em> = √(√10) exp(<em>i</em> (arctan(1/3) + 2<em>π</em>) / 2)

Then in standard rectangular form, we have

\sqrt z = \sqrt[4]{10} \left(\cos\left(\dfrac12 \arctan\left(\dfrac13\right)\right) + i \sin\left(\dfrac12 \arctan\left(\dfrac13\right)\right)\right)

and

\sqrt z = \sqrt[4]{10} \left(\cos\left(\dfrac12 \arctan\left(\dfrac13\right) + \pi\right) + i \sin\left(\dfrac12 \arctan\left(\dfrac13\right) + \pi\right)\right)

We can simplify this further. We know that <em>z</em> lies in the first quadrant, so

0 < arg(<em>z</em>) = arctan(1/3) < <em>π</em>/2

which means

0 < 1/2 arctan(1/3) < <em>π</em>/4

Then both cos(1/2 arctan(1/3)) and sin(1/2 arctan(1/3)) are positive. Using the half-angle identity, we then have

\cos\left(\dfrac12 \arctan\left(\dfrac13\right)\right) = \sqrt{\dfrac{1+\cos\left(\arctan\left(\dfrac13\right)\right)}2}

\sin\left(\dfrac12 \arctan\left(\dfrac13\right)\right) = \sqrt{\dfrac{1-\cos\left(\arctan\left(\dfrac13\right)\right)}2}

and since cos(<em>x</em> + <em>π</em>) = -cos(<em>x</em>) and sin(<em>x</em> + <em>π</em>) = -sin(<em>x</em>),

\cos\left(\dfrac12 \arctan\left(\dfrac13\right)+\pi\right) = -\sqrt{\dfrac{1+\cos\left(\arctan\left(\dfrac13\right)\right)}2}

\sin\left(\dfrac12 \arctan\left(\dfrac13\right)+\pi\right) = -\sqrt{\dfrac{1-\cos\left(\arctan\left(\dfrac13\right)\right)}2}

Now, arctan(1/3) is an angle <em>y</em> such that tan(<em>y</em>) = 1/3. In a right triangle satisfying this relation, we would see that cos(<em>y</em>) = 3/√10 and sin(<em>y</em>) = 1/√10. Then

\cos\left(\dfrac12 \arctan\left(\dfrac13\right)\right) = \sqrt{\dfrac{1+\dfrac3{\sqrt{10}}}2} = \sqrt{\dfrac{10+3\sqrt{10}}{20}}

\sin\left(\dfrac12 \arctan\left(\dfrac13\right)\right) = \sqrt{\dfrac{1-\dfrac3{\sqrt{10}}}2} = \sqrt{\dfrac{10-3\sqrt{10}}{20}}

\cos\left(\dfrac12 \arctan\left(\dfrac13\right)+\pi\right) = -\sqrt{\dfrac{10-3\sqrt{10}}{20}}

\sin\left(\dfrac12 \arctan\left(\dfrac13\right)+\pi\right) = -\sqrt{\dfrac{10-3\sqrt{10}}{20}}

So the two square roots of <em>z</em> are

\boxed{\sqrt z = \sqrt[4]{10} \left(\sqrt{\dfrac{10+3\sqrt{10}}{20}} + i \sqrt{\dfrac{10-3\sqrt{10}}{20}}\right)}

and

\boxed{\sqrt z = -\sqrt[4]{10} \left(\sqrt{\dfrac{10+3\sqrt{10}}{20}} + i \sqrt{\dfrac{10-3\sqrt{10}}{20}}\right)}

3 0
3 years ago
Read 2 more answers
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