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Vladimir [108]
4 years ago
5

Find the domain of the function.

Mathematics
1 answer:
timurjin [86]4 years ago
5 0

When taking square roots, you can't take square roots of negative roots of negative numbers. So, what will work for the domain of u(x) is what makes u(x) zero or more. We can make an inequality for that.

u(x) ≥ 0.

\sqrt{9x+27} \geq  0

9x + 27 ≥ 0 by squaring both sides

9x ≥ -27

x ≥ -3

So the domain of the function is when x ≥ -3 is true.

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Answer:

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Step-by-step explanation:

Firstly we've to find the hypotenuse of the first triangle:

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Using cos for it.

Cos 45 = adjacent / hypotenuse

0.707 = 10 / hyp

hyp = 10 / 0.707

hyp = 14.14

The hypotenuse of the first triangle is actually the base (or opposite) of the triangle.

Also, hypotenuse = x and angle is 60 degrees.

<u>So, we will use the sin ratio.</u>

sin 60 = opposite / hypotenuse

0.866 = 14.14 / x

x = 14.14 / 0.866

x = 16.3

\rule[225]{225}{2}

Hope this helped!

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