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Vladimir [108]
3 years ago
5

Find the domain of the function.

Mathematics
1 answer:
timurjin [86]3 years ago
5 0

When taking square roots, you can't take square roots of negative roots of negative numbers. So, what will work for the domain of u(x) is what makes u(x) zero or more. We can make an inequality for that.

u(x) ≥ 0.

\sqrt{9x+27} \geq  0

9x + 27 ≥ 0 by squaring both sides

9x ≥ -27

x ≥ -3

So the domain of the function is when x ≥ -3 is true.

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Given f(x) = 3x - 1 and g(x)= -x + 6, find f(-2) + g(5).<br> A. -6<br> B. 6<br> C. 8
marta [7]

Answer:

A. -6

Step-by-step explanation:

f(x)=3x-1\\\\

In order to find f(-2) we will plugin x=-2

f(-2) = 3(-2)-1\\f(-2)=(3\times(-2))-1\\f(-2)=-6-1

f(-2)=-7

g(x)=-x+6

In order to find g(5) we will plugin x=5

g(5)=-5+6

g(5)=1

f(-2)+g(5)\\=-7+1\\=-6

∴ f(-2)+g(5)=-6

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3 years ago
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Varvara68 [4.7K]

Answer:

Step-by-step explanation:

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PLSSS HELLLPPPP
-Dominant- [34]

Answer:

provided an easy explanation to give answer below

Step-by-step explanation:

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2 - 10 prime numbers are

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7 0
3 years ago
Read 2 more answers
Solve for a. 1/3(21-3a)=6-a
OverLord2011 [107]

Answer:

no solution

Step-by-step explanation:

Given

\frac{1}{3} (21 - 3a) = 6 - a ( multiply through by 3 to clear the fraction )

21 - 3a = 18 - 3a ( subtract 21 from both sides )

- 3a = - 3 - 3a ( add 3a to both sides )

0 = - 3 ← not possible

This indicates the equation has no solution

5 0
3 years ago
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