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3 years ago

Jackie exchanges 8 Kappa coins for 3 Gamma coins. Lana wants to exchange

Mathematics

2 answers:

Komok [63]3 years ago

6 0

Answer:

Step-by-step explanation:

8/3=2.66666666667

1 kappa coin=2.66666666667 gamma coins

32/2.66666666667=12

WARRIOR [948]3 years ago

4 0

Answer:

12 gamma coins

Step-by-step explanation:

We can use a ratio to solve

8 kappa 32 kappa

------------------ = ----------------

3 gamma x gamma

Using cross products

8x = 3*32

Divide each side by 8

8x/8 = 32 *3/ 8

x = 32/8 *3

x = 12 coins

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For her presentation on the Wonders of the World, Mary baked a square pyramid-shaped cake as pictured below. The slant height of

mihalych1998 [28]

Answer:

$V=196in^3$

Step-by-step explanation:

The volume of a pyramid is:

$V=\frac{A_{b}h}{3}$

where $A_{b}$ is the area of the base and $h$ is the height (the perpendicular measurement between base and highest point, not the slant height)

Since the base is a square, the area is given by:

$A_{b}=l^2$

where $l$ is the length of the side: $l=8in$ , thus:

$A_{b}=(8in)^2\\A_{b}=64in^2$

Now we need to find the height, for this we use the right triangle that forms with half of a square side (8in/2 = 4in), the slant height (10in), and the height.

In this right triangle, the slant height is the hypotenuse, the leg 1 is the unknown height, and leg 2 is half of the square side.

Using pythagoras:

$hypotenuse^2=leg1^2+leg2^2$

substituting our values, and indicating that leg 1 is height h:

$(10in)^2=h^2+(4in)^2$

$100in^2=h^2+16in^2$

and solving for the height:

$h^2=100in^2-16in^2\\h^2=84in^2\\h=\sqrt{84in^2}\\ h=9.165in$

and finally we calculate the volume using this height and the area of the base:

$V=\frac{A_{b}h}{3}$

$V=\frac{(64in^2)(9.165in)}{3} \\V=195.5in^3$

rounding to the nearest cubic inch: $V=196in^3$

4 0

3 years ago

Help me anyone ASAP snens

azamat

Answer:

thousandths

Step-by-step explanation:

5 0

3 years ago

Math help @LIEMONDER

klio [65]

First picture)
I: 5x+2y=-4
II: -3x+2y=12

add I+(-1*II):
5x+2y-(-3x+2y)=-4-12
8x=-16
x=-2

insert x=-2 into I:
5*(-2)+2y=-4
-10+2y=-4
2y=6
y=3

(-2,3)

question 6)
I: totalcost=115=3*childs+5*adults
II: 33=adults+childs
33-adults=childs

insert childs into I:
115=3*(33-adults)+5*adults
115=99-3*adults+5*adults
16=2*adults
8=adults

insert adults into II:
33-8=childs
25=childs

so it's the last option

question 7)
a) y<6 and y>2 can also be written as 2<y<6, so solution 3 exist for example
b) y>6 and y>2 can also be written as 2<6<y, so solution 7 exist for example
c) y<6 and y<2 inverse of b: y<2<6, so for example 1
d) y>6 and y<2: y<2<6<y, this is impossible as y can be only either bigger or smaller than 2 or 6

so it's the last option

question 8)
I: x+y=12
II: x-y=6

subtract: I-II:
x+y-(x-y)=12-6
2y=6
y=3

insert y into I:
x+3=12
x=9

(9,3)

question 9)
I: x+y=6
II: x=y+5

if you take the x=y+5 definition of II and substitute it into I:
(y+5)+y=6

which is the second option :)

5 0

3 years ago

3^{x^{2}}=2^{\log_{3}2}\\find\:{3}^{x}

Rashid [163]

Answer:

b r u h what

Step-by-step explanation:

6 0

2 years ago

What is the sum of the finite arithmetic series? 26 + 29 + 32 + 35 + 38 + 41 + 44

Leya [2.2K]

The sum of the finite arithmetic series of <span> 26 + 29 + 32 + 35 + 38 + 41 + 44 is 245. Arithmetic series is a sequence of number such that the difference between any term and the previous term is a constant number. When we sum a finite number of terms in the arithmetic series, we get the finite arithmetic series. </span>

4 0

4 years ago

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