Ask question

Ask question

All categories

2 years ago

11

Hiro painted his room at a rate of 8 square meters per hour. After 3 hours of painting, he had 28 square meters left to paint. L

et A(t) denote the area to paint A (measured in square meters) as a function of time t (measured in hours). What is the Functions formula? A(t)=?

1 answer:

coldgirl [10]2 years ago

5 0

Answer:

cgnnjfcjifchhgsiwjcjcbanxjdhw

You might be interested in

Pythagorean Theorem:a2 + b2 = c2 Re−write the formula solving for b2 .

gulaghasi [49]

Answer: c2 - a2 = b2

Step-by-step explanation: to isolate b2 you have to subtract a2 from both sides to get c2 - a2 = b2

6 0

2 years ago

(05.05)Polygon ABCD has the following vertices:

Kaylis [27]

Answer is option b)38.5 sq.units

Given vertices are A(-4,2) ,B(3,2),C(3,-5) and D(-4,-2)

Area of polygon is defined in the image.

If you have any doubts see the image or ask in comments box.

HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION.

4 0

2 years ago

Which function is equivalent to y = 2(x – 4)^2 + 8?

Flura [38]

Answer:

B: y = 2x² - 16x + 40

Step-by-step explanation:

You can find this simply by expanding the given function:

y = 2(x - 4)² + 8

y = 2(x² - 8x + 16) + 8

y = 2x² - 16x + 32 + 8

y = 2x² - 16x + 40

8 0

2 years ago

The average college lecture hall (auditorium) can seat 60 students with a standard deviation of 21. Assume that a total of 60 le

fiasKO [112]

Answer:

The standard deviation of the sample mean is $\sigma _ {\= x } = 2.711$

Step-by-step explanation:

From the question we are told that

The mean is $\= x = 60$

The standard deviation is $\sigma = 21$

The sample size is $n = 60$

Generally the standard deviation of the sample mean is mathematically represented as

$\sigma _ {\= x } = \frac{\sigma }{\sqrt{n} }$

substituting values

$\sigma _ {\= x } = \frac{ 21 }{\sqrt{60} }$

$\sigma _ {\= x } = 2.711$

4 0

2 years ago

Lucio quiere repartir su colección de estampillas entre la mayor cantidad de amigos pero de manera que todos reciban la misma ca

Daniel [21]

Answer:

Lucio podrá armar 5 grupos iguales de estampillas.

Step-by-step explanation:

El problema plantea un caso de distribución mediante la aplicación del divisor común mayor a todos los números involucrados. Para ello, primero debemos analizar los divisores de cada uno de estos números:

-30: divisible por 2, 3, 5, 6, 10, 15 y 30.

-75: divisible por 3, 5, 15, 25 y 75.

-160: divisible por 2, 4, 5, 8, 10, 16, 20, 32, 40, 80 y 160.

Así, podemos ver que el divisor común mayor a los tres números es 5, ya que 30, 75 y 160 dan como resultado un número entero tras ser divididos por 5.

Entonces, para poder repartir equitativamente sus estampillas entre la mayor cantidad de amigos posibles, deberá repartir 6 estampillas de animales, 15 estampillas de flores y 32 estampillas de ciudades a 5 amigos. De esta manera, Lucio podrá armar 5 grupos iguales de estampillas.

4 0

3 years ago