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dimulka [17.4K]
3 years ago
12

In a standard normal distribution 95% of the data is within +/- _______standard deviations of the mean.

Mathematics
2 answers:
raketka [301]3 years ago
8 0
Your answer is 2 okay
dybincka [34]3 years ago
6 0

Answer:

2

Step-by-step explanation:

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Number of minutes 1 2 3 4 5 6 7 8 9 10
umka21 [38]

Answer: please find the attached file for the graph.

Step-by-step explanation:

Number of minutes 1 2 3 4 5 6 7 8 9 10Number of trainees 2 3 5 10 15 30 25 15 10 5

Given that data set above, the time in minutes will be on the x axis while the number of trainees will be in the y axis.

In bar chart, the bars will not touch each other.

Please find the attached file for the solution and figure

4 0
3 years ago
Plss tell me the ans​
brilliants [131]

Answer:

I dont know if this is right but I think its 125/343

4 0
3 years ago
Explain the significance and uses for statistics in daily life​
scZoUnD [109]

Answer:

Statistics are the sets of mathematical equations that we used to analyze the things. It keeps us informed about, what is happening in the world around us. Statistics are important because today we live in the information world and much of this information's are determined mathematically by Statistics Help.

4 0
3 years ago
Maria, Keisha, Jo, and Leah wear jerseys numbered 5, 8, 13, and 36, but not necessarily in that order. The girl wearing 8 has a
Anna [14]
Jo - 36
Maria - 5
Keisha  - 8
Leah - 13

8 0
3 years ago
Read 2 more answers
Please help fassssst
Zarrin [17]

Answer:

\dfrac{9}{2}

Step-by-step explanation:

You can do this using the quadratic equation:

x =\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}

Let's first setup our expression:

4x² + 12x = 135

the quadratic formula is:

ax² + bx + c = 0

4x² + 12x - 135 = 0

Then:

a = 4

b = 12

c = -135

Now we plug in our coefficients and solve:

x =\dfrac{-12\pm\sqrt{12^{2}-4(4)(-135)}}{2(4)}

We solve for both to determine the positive one:

x =\dfrac{-12+ \sqrt{12^{2}-4(4)(-135)}}{2(4)}              x =\dfrac{-12- \sqrt{12^{2}-4(4)(-135)}}{2(4)}

x =\dfrac{-12+ \sqrt{144+2160}}{8}                        x =\dfrac{-12- \sqrt{144+2160}}{8}

x =\dfrac{-12+ \sqrt{2304}}{8}                                 x =\dfrac{-12- \sqrt{2304}}{8}

x =\dfrac{-12+ 48}{8}                                        x =\dfrac{-12- 48}{8}

x =\dfrac{36}{8} = \dfrac{9}{2}                                           x =\dfrac{-60}{8} = \dfrac{-15}{2}

So if you are looking for a positive solution, just take the positive one as x.

8 0
3 years ago
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