3 years ago

Evaluate log base 12 of y^2, given log base 12=16

Mathematics

1 answer:

Ostrovityanka [42]3 years ago

5 0

Answer:

y = 12^8

Step-by-step explanation:

Log base 12, y^2 = 16

y2 = 12^16

y = sqrt ( 12^16) = (12^16)^1/2

y = 12^8

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