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skelet666 [1.2K]
3 years ago
14

What is the vertex of the quadratic function fix=(x-8)(x-2)

Mathematics
1 answer:
VikaD [51]3 years ago
8 0

Answer:

Vertex: (5, -9)

Step-by-step explanation:

fix = (x-8)(x-2)

fix = x^2 - 2x - 8x + 16

fix = x^2 - 10x + 16

a = 1, b = -10, and c = 16

To find vertex:

x = -b/2a

x = -(-10)/2(1)

x = 10/2

x = 5

y = 5^2 - 10(5) + 16

y = 25 -50 + 16

y = -9

Vertex: (5, -9)

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choice number 2) 10 in, 18.5 in 31.5 in

Step-by-step explanation:

we collect and evaluate the like terms.like terms means the ones that can be evaluated. like 2y and 7y are like terms. they either can be added or subtracted to get an answer . 7y-2y =5y. but you cant subtrac or add 7y  with 5 because they are not like terms.

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If you need any clarification or more explanation pls do mention at the comment section so that i can help more thx

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Step-by-step explanation:

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