Assume that the following confidence interval for the difference in the mean length of male (sample 1) and female babies (samp
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The critical value becomes 2.584 for two tailed test since we have to reject the null hypothesis, t >2.584 or t < -2.584 test stat lie in the rejection region, we have to reject the null hypothesis or claim incorrect.
Data;
- mean = 5.82
- s = 4.93
- n = 600
Let's calculate the t-value
Substitute the values into the equation and solve;
The t-value is 4.079.
The allowed significance value = 0.01
The degree of freedom is n -1, which becomes 600 - 1 = 599.
The critical value becomes 2.584 for two tailed test since we have to reject the null hypothesis, t >2.584 or t < -2.584 test stat lie in the rejection region, we have to reject the null hypothesis or claim incorrect.
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