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Nitella [24]
2 years ago
13

What is the decimal form for nine and fifteen thousandths?

Mathematics
1 answer:
nikdorinn [45]2 years ago
3 0
The decimal form for nine and fifteen thousandths is 09.15
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Degrees Celsius and degrees Fahrenheit are related by C=5/9(F-32).What is F in terms of C?
valina [46]

We are given: Degrees Celsius and degrees Fahrenheit are related by formula

C=\frac{5}{9} (F-32)

To find : Solve formula for F in terms of C.

Solution: We have , C=\frac{5}{9} (F-32)

First we need to get rid 9 from right denominator.

In order to get rid 9 from right denominator, we need to multiply equation both sides by 9.

9*C=9*\frac{5}{9} (F-32)

9C = 5 (F-32).

Distributing 5 on right side over (F-32), we get 5*F - 5*32 = 5F - 160.

9C = 5F - 160.

Adding 160 on both sides,

9C+160 = 5F - 160+160.

9C+160 =5F

Dividing both sides by 5, we get

(9C+160)/5 =5F/5.

\frac{9C+160}{5}=F

Splitting fraction 1/5, we get

F= \frac{1}{5} (9C+160).




4 0
3 years ago
Prove the identity secxcscx(tanx+cotx)=2+tan^2x+cot^2x
svetlana [45]
Hello,

sec(x)= \dfrac{1}{cos(x)} \\

cosec(x)= \dfrac{1}{sin(x)} \\

sec(x)*cosec(x)*(tg(x)+cotg(x))=\dfrac{1}{cos(x)}* \dfrac{1}{sin(x)}*( \frac{sin(x)}{cos(x)} +\frac{cos(x)}{sin(x)})\\

= \dfrac{sin^2(x)+cos^2(x)}{sin^2x*cos^2x} \\

= \dfrac{1}{sin^2x*cos^2x} \\


==============================================================
2+tg^2(x)+cotg^2(x)=2+ \dfrac{sin^2x}{cos^2x} + \dfrac{cos^2x}{sin^2x} \\

=2+ \dfrac{sin^4x+cos^4x}{sin^2x*cos^2x} \\

=\dfrac{2*sin^2x*cos^2x+sin^4x+cos^4x}{sin^2x*cos^2x} \\

= \dfrac{(sin^2x+cos^2x)^2}{sin^2x*cos^2x}} \\

= \dfrac{1}{sin^2x*cos^2x}} 

8 0
3 years ago
Read 2 more answers
The number of phone calls between two​ cities, N, during a given time period varies directly as the populations p 1 and p 2 of t
kherson [118]

Answer:

∴73,563 calls are made between two cities with populations of 100,000 and 160,000 that are 435 miles apart.

Step-by-step explanation:

Given that,

The number of phone calls between two cities (N )

  • directly proportional as the value of populations p_1  and p_2  of two cities.
  • Inversely varies as the magnitude of distance (d).

N\propto\frac{p_1p_2}{d}

N=k.\frac{p_1p_2}{d}

Given that,

N=18,000, d=310 miles,  p_1=15,500 and p_2=180,000

18,000=k.\frac{15,500\times 180,000}{310}

\Rightarrow k=\frac{18,000\times310}{15,500\times 180,000}

\Rightarrow k=\frac{31}{15,500}

Now,

N=? , d=435 miles,  p_1=100,500 and p_2=160,000

N=\frac{31}{15,500}.\frac{100,000\times 160,000}{435}

\Rightarrow N\approx 73,563

∴73,563 calls are made between two cities with populations of 100,000 and 160,000 that are 435 miles apart.

5 0
3 years ago
Reuben walks 2.5 km every day. How far does he walk in 7 days?<br> Write your answer in meters.
Fed [463]

Answer:

1day=2.5km

7days=?

<u>7</u><u>×</u><u>2</u><u>.</u><u>5</u>

1

=17.5km

1km=1000m

27.5km=?

=27500m

5 0
2 years ago
Evaluate if x = 2.<br> 9x + 13<br> A) 5 <br> B) 18 <br> C) 24 <br> D) 31
san4es73 [151]
The Answer is

D) 31 Because 9x+13, 9(2)+13, 18+13, 31
8 0
3 years ago
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