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3 years ago

find an equation of a line parallel to y=3x+2 and passes through the point (1,3). Write answer form y=mx+b

2 answers:

8 0

Because they are parallel they have the same slope so m= 3
and then we can use the formula
(y-yo)=m (x-xo)
where 1 is xo and 3 is yo
after substitution
y-3=3x-3

y=3x+0

Komok [63]3 years ago

4 0

If the line is parallel, it will have the same slope but a different y intercept.
So, so far y=3x+b.
Because we know that this parallel line goes through (1,3), we can substitute these co-ordinates to get b:
3=(3 x 1)+b
3=3+b
0=b
So the equation of the parallel line is as follows:
y=3x+0

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Step-by-step explanation:

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Closure with respect to addition:

Let consider polynomials $p_{1}$ and $p_{2}$ such that:

$p_{1} = \Sigma \limits_{i=0}^{m} \,a_{i}\cdot x^{i}$ and $p_{2} = \Sigma \limits_{i=0}^{n}\,b_{i}\cdot x^{i}$ , where $m \geq n$

$p_{1}+p_{2} = \Sigma \limits_{i=0}^{n}\,(a_{i}+b_{i})\cdot x^{i} + \Sigma_{i=n+1}^{m}\,a_{i} \cdot x^{i}$

Hence, polynomials are closed with respect to addition.

Closure with respect to multiplication:

Let be $p_{1}$ a polynomial such that:

$p_{1} = \Sigma \limits_{i=0}^{m} \,a_{i}\cdot x^{i}$

And $\alpha$ an scalar. If the polynomial is multiplied by the scalar number, then:

$\alpha \cdot p_{1} = \alpha \cdot \Sigma \limits_{i = 0}^{m}\,a_{i}\cdot x^{i}$

Lastly, the following expression is constructed by distributive property:

$\alpha \cdot p_{1} = \Sigma \limits_{i=0}^{m}\,(\alpha\cdot a_{i})\cdot x^{i}$

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