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rusak2 [61]
3 years ago
6

HELP!!! 20 POINTS!!! URGENT!!!

Mathematics
1 answer:
VashaNatasha [74]3 years ago
8 0

We know that :

\clubsuit  ln(A) - ln(B) = ln(\frac{A}{B})

\clubsuit  aln(x) = ln(x)^a

\clubsuit  ln(A) + ln(B) = ln(AB)

Using above ideas we can solve the Problem :

⇒ \frac{3}{8}ln(x + 3) = ln(x + 3)^\frac{3}{8}

⇒ ln(x - 3) - ln(x + 3)^\frac{3}{8} = ln[\frac{(x - 3)}{(x + 3)^\frac{3}{8}}]

⇒ 4ln[\frac{(x - 3)}{(x + 3)^\frac{3}{8}}] = ln[\frac{(x - 3)}{(x + 3)^\frac{3}{8}}]^4 = ln[\frac{(x - 3)^4}{(x + 3)^\frac{3}{2}}]

⇒ \frac{1}{3}lnx + ln[\frac{(x - 3)^4}{(x + 3)^\frac{3}{2}}] = ln(x)^\frac{1}{3} + ln[\frac{(x - 3)^4}{(x + 3)^\frac{3}{2}}] = ln[\frac{\sqrt[3]{x}(x - 3)^4}{\sqrt{(x + 3)^{3}}}]

Option 3 is the Answer

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Hope this helps you! :D

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Now, put y = 0, 
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