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Vlada [557]
3 years ago
6

If you want to graph the relationship to compare the unit prices, what should the x- axis and the y-axis represent

Mathematics
1 answer:
Yuri [45]3 years ago
5 0

Answer:

it represents the following

read in my explanation

Step-by-step explanation:

A bar chart is a graph with rectangular bars. The graph usually compares different categories. Although the graphs can be plotted vertically (bars standing up) or horizontally (bars laying flat from left to right), the most usual type of bar graph is vertical.

The horizontal (x) axis represents the categories; The vertical (y) axis represents a value for those categories. In the graph below, the values are percentages.

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El valor del 0 en el número 60,152?
andreev551 [17]

The value of the 0 in the number 60,152 is the thousands place.

6 = ten thousand

0 = thousand

1 = hundreds

5 = tens

2 = ones

Hope helps!-Aparri

8 0
3 years ago
Rewrite the equation y−2=−3/2(x+6) in standard form.
navik [9.2K]

For this case we have that by definition, the standard form of the equation of the line is given by:

ax + by = c

We have the following equation:

y-2 = - \frac {3} {2} (x + 6)

We manipulate the equation algebraically:

y-2 = - \frac {3} {2} x- \frac {3 * 6} {2}\\y-2 = - \frac {3} {2} x \frac {18} {2}\\y-2 = - \frac {3} {2} x-9\\y-2 + 9 = - \frac {3} {2} x\\y-7 = - \frac {3} {2} x\\2 (y-7) = - 3x\\2y-14 = -3x\\3x + 2y = 14

Finally, the equation is:

3x + 2y = 14

Answer:

3x + 2y = 14

3 0
3 years ago
Need Help on this, First RIGHT answer gets brainliest :)
yaroslaw [1]
The answer is 50% as half the circle is shaded!
7 0
3 years ago
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Click on file! ;D thank you! <3​
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3 0
3 years ago
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The mean score on a driving exam for a group of driver's education students is 84 points, with a standard deviation of 4 points.
Anastasy [175]

Using Chebyshev's Theorem, it is found that:

At least 75% of the exam scores fall between 76 and 92.

---------------------------

  • Chebyshev's Theorem states that the percentage of measures within k standard deviations of the mean is of at least 100(1 - \frac{1}{k^{2}}).
  • With k = 2, that is, within 2 standard deviations of the mean:

P = 100(1 - \frac{1}{2^{2}})

P = 100(1 - \frac{1}{4})

P = 100(\frac{3}{4})

P = 75

  • At least 75% of the measures are within 2 standard deviations of the mean.

84 - 2(4) = 76

84 + 2(4) = 92

  • Thus, at least 75% of scores between 76 and 92.

A similar problem is given at brainly.com/question/23612895

8 0
2 years ago
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