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Troyanec [42]
2 years ago
8

a woman at a point a on the shore of a circular lake with radius 1.2 mi wants to arrive at the point B diametrically opposite A

on the other side of the lake in the shortest possible time (see the figure). she can walk at the rate of 5 mi/h from C to B and row a boat at 3.5 mi/h from A to C . setting T (x) function to the time by interlaced AC, x is interlacted AC. how to move for shortest.

Mathematics
1 answer:
kenny6666 [7]2 years ago
4 0

If she arrives by boat;

The distance she needs to row = Lake diameter

Distance = Lake diameter = 2 x Radius

Boat distance = 2 x 2 miles = 4 miles

So;

When moving on foot

The distance that needs to be moved D = Half of the circle circle

∴ D = π × Radius

The distance that needs to be moved D = π × 2 miles = 2π Miles

Arc length = Radius × θ

String length = radius x 2 x sin (θ / 2)

0 ≤ θ ≤ π, 0 ≤ sin (θ / 2) ≤ 1

Learn more here shore of a circular at

brainly.com/question/16597466

#SPJ10

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What is the gcf of 3/7 and 4/9?
LiRa [457]

Answer:

  1/63

Step-by-step explanation:

There are a couple of ways to do this.

<h3>1) </h3>

Look for the GCF of the numerators when a common denominator is used.

  GCF(3/7, 4/9) = GCF(27/63, 28/63) = (1/63)·GCF(27, 28)

  GCF(3/7, 4/9) = 1/63

__

<h3>2) </h3>

Use Euclid's algorithm. If the remainder from division of the larger by the smaller is zero, then the smaller is the GCF; otherwise, the remainder replaces the larger, and the algorithm repeats.

  (4/9)/(3/7) = 1 remainder 1/63*

  (3/7)/(1/63) = 27 remainder 0

The GCF is 1/63.

__

* The quotient is 28/27 = 1 +1/27 = 1 +(1/27)(3/7)/(3/7) = 1 +(1/63)/(3/7) or 1 with a remainder of 1/63.

_____

<em>Additional comment</em>

3/7 = (1/63) × 27

4/9 = (1/63) × 28

3 0
2 years ago
Write an equation in slope-intercept form for the line that is parallel to y = −4x − 3 and that passes through the point (−2, 4)
Neporo4naja [7]
Since it's parallel, then the slope is the same
use the point slope formula and plug in the slope and point
y-y1=m(x-x1)
y-4=-4(x+2)
y-4=-4x-8
y=-4x-4
this is in slope intercept form
6 0
4 years ago
(x-4)/5=9-(2x-41)/9
jok3333 [9.3K]
For this question, you have to take Least Common Multiplier for which in this case will be "45" as, the denominators can get similar and get multiplied by a same value to form a similar expression. This allows us to cancel out them by common factors. Full process shown below.

\mathbf{Given \: \: Expression: \: \dfrac{x - 4}{5} = 9 - \dfrac{2x - 41}{9}}

\mathbf{\dfrac{x - 4}{5} \times 45 = 9 \times 45 - \dfrac{2x - 41}{9} \times 45}

\mathbf{9(x - 4) = 405 - 5 (2x - 41)}

\mathbf{9x - 36 = 405 - 10x + 205}

\mathbf{9x - 36 = - 10x + 610}

\mathbf{9x - 36 + 36 = - 10x + 610 + 36}

\mathbf{9x = - 10x + 646}

\mathbf{9x + 10x = - 10x + 646 + 10x}

\mathbf{19x = 646}

\mathbf{\dfrac{19x}{19} = \dfrac{646}{19}}

\mathbf{\therefore \quad x = 34}

\boxed{\mathbf{\underline{\therefore \quad Final \: \: Answer \: \: is; \: \: x = 34}}}

Hope it helps.
3 0
3 years ago
If t=0 in 1980, find the value of A. Round answer to the nearest million.
balu736 [363]

P=Ae^kt

225 = 210 * e^(k*(1990-1980)

225/210=e^10k ln(225/210)=10k

k=ln(225/210)/10=0.0069

P = 210*e^(0.0069t)

for 2000 ===> t = 2000-1980=20

P = 210*e^(0.0069*20)

P=241.0749=241

4 0
4 years ago
Arielle wants to make a circular garden. She has enough fencing for a garden circumference of 15 feet. There is a 7-foot gap bet
lesantik [10]

Answer:

yes

Step-by-step explanation:

We need to check if the circle with a circumference of 15 feet is smaller then 7 feet. If so it possible.

Formule for circular circumference = pi * diameter, which should be 15.

So pi * d =15

There fore d = 15/pi

d = 4.77464829275686 feet, which is smaller then 7 feet, so it will fit easilly.

3 0
3 years ago
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