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Troyanec [42]
2 years ago
8

a woman at a point a on the shore of a circular lake with radius 1.2 mi wants to arrive at the point B diametrically opposite A

on the other side of the lake in the shortest possible time (see the figure). she can walk at the rate of 5 mi/h from C to B and row a boat at 3.5 mi/h from A to C . setting T (x) function to the time by interlaced AC, x is interlacted AC. how to move for shortest.

Mathematics
1 answer:
kenny6666 [7]2 years ago
4 0

If she arrives by boat;

The distance she needs to row = Lake diameter

Distance = Lake diameter = 2 x Radius

Boat distance = 2 x 2 miles = 4 miles

So;

When moving on foot

The distance that needs to be moved D = Half of the circle circle

∴ D = π × Radius

The distance that needs to be moved D = π × 2 miles = 2π Miles

Arc length = Radius × θ

String length = radius x 2 x sin (θ / 2)

0 ≤ θ ≤ π, 0 ≤ sin (θ / 2) ≤ 1

Learn more here shore of a circular at

brainly.com/question/16597466

#SPJ10

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Answer: Children tickets cost 7.50

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Step-by-step explanation:

Let a represent adult tickets

Let c represent child tickets

On the first day she sells 6 adult tickets and 5 children tickets for total of 112.50. This can be written as:

6a + 5c = 112.50 ...... equation i

On the second day she sells 8 adult tickets and 4 children tickets for the total 130. This can be written as:

8a + 4c = 130 ....... equation ii

6a + 5c = 112.50 ...... equation i

8a + 4c = 130 ....... equation ii

Multiply equation i by 4

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24a + 20c = 450 ........ equation iii

40a + 20c = 650 ......... equation iv

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a = 12.50

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From equation ii,

8a + 4c = 130

8(12.50) + 4c = 130

100 + 4c = 130

4c = 130 - 100

4c = 30

c = 30/4

c = 7.50

Children tickets cost 7.50

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3 years ago
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