F(x)=8x^2-2x+3 g(x)=12x^2+4x-3 what is h(x)=f(x)-g(x)?

Mathematics

2 answers:

Trava [24]3 years ago

6 0

Answer: $h(x)=-4x^2-6x+6$

Step-by-step explanation:

To find the function h(x), you need to subtract the function $f(x)=8x^2-2x+3$ and the function $g(x)=12x^2+4x-3$ .

$h(x)=f(x)-g(x)\\h(x)=8x^2-2x+3-(12x^2+4x-3)$

Distribute the negative sign:

$h(x)=8x^2-2x+3-12x^2-4x+3$

Now you can add the like terms:

$h(x)=-4x^2-6x+6$

Therefore, you get that the function h(x) is:

$h(x)=-4x^2-6x+6$

Softa [21]3 years ago

6 0

Answer:

h(x) = - 4x² - 6x + 6

Step-by-step explanation:

It is given that,

f(x) = 8x² - 2x + 3 and

g(x) = 12x² + 4x - 3

<u>To find h(x)</u>

h(x) = f(x) - g(x)

h(x) = ( 8x² - 2x + 3) - (12x² + 4x - 3)

= 8x² - 2x + 3 - 12x² - 4x + 3

= 8x² - 12x² - 2x - 4x + 3 + 3

= - 4x² - 6x + 6

Therefore h(x) = - 4x² - 6x + 6

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Setler79 [48]

Answer:

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Step-by-step explanation:

Z-score:

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$Z = \frac{X - \mu}{\sigma}$

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In this question:

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