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KATRIN_1 [288]
3 years ago
14

The server core installation option in windows server 2012 effectively removes _______:

Computers and Technology
1 answer:
Stels [109]3 years ago
6 0
Answer = <span>Graphical User Interface</span>
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Your first submission for the CIS 210 Course Project should include the following functionality: - Requests the user to input hi
Viefleur [7K]

Answer:

In Java:

import java.util.*;

public class Main{

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

 String name;

 System.out.print("First name: ");

 name = input.next();

 name= name.substring(0, 1).toUpperCase() + name.substring(1).toLowerCase();

 System.out.print(name);

}

}

Explanation:

This declares name as string

 String name;

This prompts the user for first name

 System.out.print("First name: ");

This gets the name from the user

 name = input.next();

This capitalizes the first letter of name and makes the other letters to be in lowercase

 name= name.substring(0, 1).toUpperCase() + name.substring(1).toLowerCase();

This prints the formatted name

 System.out.print(name);

5 0
3 years ago
Which statements best describe slaves in ancient times? Select all that apply.
Romashka-Z-Leto [24]

Answer:

Slaves are the people thought as conquered People

Explanation:

In ancient times, slaves works without any remunerations. These people are captured or purchased by rich peoples. Their whole life spends in slavery. The people who are also prisoners of wars worked as slaves for their rest of the life.

5 0
2 years ago
Ld' is the instruction with the longest latency on the CPU from Section 4.4 (in RISC-V text). If we modified ld and sd so that t
antiseptic1488 [7]

Answer:

See explaination

Explanation:

a)

The primary factors that influence the program's speed on a new CPU are given as:-

CPU Clock speed where the speed of the process instructions is being measured.

Multi-core which is when the transistors work faster than respective CPU.

Cache which helps to note that the transition of data is smooth and fast.

b)

So, there are two CPUs suppose the old one as 'A' and the modified one as 'B'.

'A' has following features---

It takes more time to execute program as it has more clock cycle time or we can say it has low clocking rate or low speed in terms of MHz or GHz. Clock rate is the inverse of Clock Cycle Time. When you will increase the clocking rate of CPU, it will get faster and then Clock Cycle Time will get reduced.

It has less instructions provided.

'B' has following features----

It takes less time to execute program as it has less clock cycle time or we can say it has high clocking rate or high speed in terms of MHz or GHz.

It has more instructions provided.

The performance of CPU depends upon 2 factors:

The number and types of instructions that are executed by the CPU

How fast the CPU can execute those instructions?

So, overall CPU B is better as it has less execution time than CPU A but the performance will always depend upon the number and type of instructions executed by the CPU so it may vary.

Please refer to attachment for instructions and formulas.

8 0
3 years ago
Who made the first electronic device?
emmasim [6.3K]
Joseph Henry in about 1835. He is American and he made something called a relay.
6 0
2 years ago
Assume you are given three variables, revenue, expenses, and profit, all of type Money (a structured type with two int fields, d
Andre45 [30]

Answer:

if(revenue.cents - expenses.cents < 0){

profit.dollars = revenue.dollars - expenses.dollars - 1;

profit.cents = 1 - revenue.cents - expenses.cents;

}

else{

profit.dollars = revenue.dollars - expenses.dollars;

profit.cents = revenue.cents - expenses.cents;

}

Explanation:

We know that profit is given as: revenue - expenses from the question.

From the given expression above;

if(revenue.cents - expenses.cents < 0)

then profit.dollar will be revenue.dollars - expenses.dollars - 1; the 1 is to be carry over to the cent part. And the profit.cent will be 1 - revenue.cents - expenses.cents;

else the profit.dollars and the profit.cent is computed directly without needing to carry over:

profit.dollars = revenue.dollars - expenses.dollars;

profit.cents = revenue.cents - expenses.cents;

7 0
2 years ago
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