Answer:
Side of 40 and height of 20
Step-by-step explanation:
Let s be the side of the square base and h be the height of the box. Since the box volume is restricted to 32000 cubic centimeters we have the following equation:
Assume that we cannot change the thickness, we can minimize the weight by minimizing the surface area of the tank
Base area with open top
Side area 4hs
Total surface area
We can substitute
To find the minimum of this function, we can take the first derivative, and set it to 0
Answer:
(-3,5)
Step-by-step explanation:
Rewrite in vertex form and use this form to find the vertex.
I would say choice A
but im not absolutely sure
1. Subtract 3 from both sides:
y - 3 = 8x
2. Divide both sides by 8:
y - 3/8 = x
3. Switch sides:
x = y - 3/8
If it is the longest side then:
5^2+4^2=x^2
Where x= sqrt41
If it is the shortest side then:
4^2+x^2=5^2
Where x=3
Sqrt41-3= 3.4