F(x)=2^x+6
let f(x) = n
f^-1(n) = x
x = 2^n + 6
x - 6 = 2^n
2^n = x - 6
log 2^n = log (x-6)
n log 2 = log (x-6)
n = (x-6)/2
f^-1(x) = (x-6)/2
Answer:
The composite function;
f(g(x) = 2x^2 + 15
Step-by-step explanation:
Given f(x) = 2x + 1 and g(x) = x^2 + 7 ;
we want to find f(g(x))
This is simply a composite function which involves fixing the function g(x) into f(x)
Thus, we have
f(g(x)) = 2(x^2 + 7) + 1
f(g(x)) = 2x^2 + 14 + 1
f(g(x)) = 2x^2 + 15
Answer:
You didnt ask a question or link any work?
Step-by-step explanation:???
Answer:
D is the midpoint of AC Given
∠BDC ≅ ∠BDA Given
BD ≅ BD Reflexive Property
AD ≅ DC Definition of line segment bisector
ΔADB ≅ ΔCBD CPCTC (Congruent Parts of Congruent Triangles are Congruent)
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Answer:
The answer is 3720 and it's correct
Step-by-step explanation:
Hope I am helping you