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2 years ago

Help please i need help please

Mathematics

1 answer:

Irina-Kira [14]2 years ago

6 0

Answer:

Acute

Step-by-step explanation:

The angle is 5 degrees.

Acute angles are angles between 0-90

Right angles are angles measuring 90 degrees

Obtuse angles are angles between 90-180

Therefore this angle is Acute

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Wilton collected $8.50 in dimes and quarters while cleaning his father's truck. If the number of quarters is 3 times the number

dusya [7]

Answer:

Wilton found 10 dimes while cleaning his father's truck.

Step-by-step explanation:

Given that:

Total amount collected = $8.50 = 8.50*100 = 850 cents

Let,

x be the number of dimes

y be the number of quarters

According to given statement,

10x+25y=850 Eqn 1

y = 3x Eqn 2

Putting y=3x in Eqn 1

$10x+25(3x)=850\\10x+75x=850\\85x=850$

Dividing both sides by 85

$\frac{85x}{85}=\frac{850}{85}\\x=10$

As x represents dimes, therefore, number of dimes is 10.

Hence,

Wilton found 10 dimes while cleaning his father's truck.

8 0

3 years ago

Rewrite using a fractional exponent<br><br> <img src="https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B7%5E2%7D" id="TexFormula1" title=

tangare [24]

Answer:

$7^{\frac{1}{3} }$

Step-by-step explanation:

Using the rule of exponents

$\sqrt[n]{a^{m} }$ ⇔ $a^{\frac{m}{n} }$ , then

$\sqrt[6]{7^{2} }$ = $7^{\frac{2}{6} }$ = $7^{\frac{1}{3} }$

8 0

3 years ago

Write the equation y=-1/2x+3 in standard form. how do I do this?

Lapatulllka [165]

Standard form is ax + by = c. Begin our transformation by multiplying both sides by 2 to get rid of the fraction. Notice that ax + by = c does not allow for fractions. Doing that multiplication gives us 2y=-x + 3. Now move the x over by the y by addition. x + 2y = 3. And there you go!

7 0

3 years ago

Read 2 more answers

Need help with a simple problem 2^x=3^x+1

KiRa [710]

For $x\ \textgreater \ 0$ , $2^x\ \textless \ 3^x$ , all the more $2^x\ \textless \ 3^x+1$ , therefore no solution.

For $x=0$ , we have $2^0=3^0+1 \Rightarrow 1=1+1 \Rightarrow 1=2$ . Obviously that' false.

For $x\ \textless \ 0$ both $2^x$ and $3^x$ , where $2^x\ \textgreater \ 3^x$ , belong to the range $(0,1)$ , then $3^x+1$ belong to the range $(1,2)$ .
Those ranges don't have a common part, therefore, again, no solution.

So, the equation $2^x=3^x+1$ doesn't have a solution.

4 0

3 years ago

Help pleaseeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Ann [662]

Hey!

so for the first one its 60°, and for the second one its 1/6

3 0

3 years ago