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2 years ago

Help please i need help please

Mathematics

1 answer:

Irina-Kira [14]2 years ago

6 0

Answer:

Acute

Step-by-step explanation:

The angle is 5 degrees.

Acute angles are angles between 0-90

Right angles are angles measuring 90 degrees

Obtuse angles are angles between 90-180

Therefore this angle is Acute

You might be interested in

Convert the decimal 0.92¯¯¯ to a fraction.

aev [14]

Answer:

23/25 when reduced to the simplest form.

Step-by-step explanation:

write down the number as a fraction of one

0.92 = 0.92/1

so we multiply both numerator and denominator by 100

Then 0.92/1 = ( 0.92x100) / ( 1x100)

= 92/100

Now reduce the numerator and denominator by GCD between in this case

GCD ( 92,100) = 4

so, 92/ 4

100/ 4

=23/25

3 0

3 years ago

Hannah has $3.10 in her piggy bank in nickels and quarters. If there are 22 coins in her piggy bank, how many are nickels and ho

PIT_PIT [208]

Answer:

$12\ nickel$

$10\ quarter$

Step-by-step explanation:

we know that

$1\ nickel=\$0.05$

$1\ quarter=\$0.25$

Let

x------> the number of nickel coins

y-----> the number of quarter coins

we know that

$x+y=22$

$x=22-y$ -----> equation A

$0.05x+0.25y=3.10$ ----> multiply by 100 both sides

$5x+25y=310$ -----> equation B

Substitute equation A in equation B and solve for y

$5(22-y)+25y=310$

$110y-5y+25y=310$

$20y=310-110$

$20y=200$

$y=10\ quarter$

$x=22-y$ ------> $x=22-10=12\ nickel$

7 0

3 years ago

Please help ASAP is this correct?

emmasim [6.3K]

Answer:

yess that is correct

Step-by-step explanation:

18<27

7 0

3 years ago

Read 2 more answers

Simplify 12cm to 2.5mm

julia-pushkina [17]

Given:

12cm to 2.5mm

To find:

The simplified for of given statement.

Solution:

We know that,

1 cm = 10 mm

12 cm =120mm

We have,

12cm to 2.5mm

It can be written as

$\dfrac{12\ cm}{2.5\ mm}=\dfrac{120\ mm}{2.5 mm}$

$\dfrac{12\ cm}{2.5\ mm}=\dfrac{120}{2.5}$

$\dfrac{12\ cm}{2.5\ mm}=48$

Therefore, the value of 12 cm to 2.5 mm is 48 or 48:1.

7 0

3 years ago

Meg rowed her boat upstream a distance of 45 mi and then rowed back to the starting point. The total time of the trip was 14 hou

Montano1993 [528]

Recall your d = rt.

so hmm is about the same as the other one... so say the boat has a speed rate of "b", well, going downstream the boat goes say " b + 2 ", because the current is adding to it, and going upstream is " b - 2 " because the current is eroding from it.

So if the whole trip took 14 hours, say it took "t" hours going upstream, then going downstream it took the slack or " 14 - t ".

Also notice, the trip forth and back is the same 45 miles.

$\bf \begin{array}{lccclll}
&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
Upstream&45&b-2&t\\
Downstream&45&b+2&14-t
\end{array}
\\\\\\
\begin{cases}
45=t(b-2)\implies \frac{45}{b-2}=\boxed{t}\\\\
45=(b+2)(14-t)\\
----------\\
45=(b+2)\left( 14- \boxed{\frac{45}{b-2}}\right)
\end{cases}
\\\\\\
\cfrac{45}{b+2}=14- {\cfrac{45}{b-2}}\implies \cfrac{45}{b+2}=\cfrac{14(b-2)~-~45}{b-2}$

$\bf \cfrac{45}{b+2}=\cfrac{14b-28-45}{b-2}\implies \cfrac{45}{b+2}=\cfrac{14b-73}{b-2}
\\\\\\
45(b-2)=(b+2)(14b-73)\implies 45b-90=14b^2-45b-146
\\\\\\
0=14b^2-90b-56\implies 0=7b^2-45b-28
\\\\\\
0=(7b+4)(b-7)\implies b=
\begin{cases}
-\frac{4}{7}\\\\
\boxed{7}
\end{cases}$

6 0

3 years ago