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aksik [14]
3 years ago
12

Use the distributive property to simplify each expression (7+6w)6

Mathematics
2 answers:
leva [86]3 years ago
5 0
42+36w

7 x 6 + 6w x 6

Multiply to get:

42+36w

Brainliest?
bija089 [108]3 years ago
4 0

Answer:

42+ 36w

Step-by-step explanation:

You multiple all numbers in the parenthesis with the number directly outside of it. 6x6=36(w) and 7x6=42. You cant simplify any further.

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7w + (-11w)

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The graph of a system of parallel lines will have no solutions. (1 point) Select one: a. Always b. Sometimes c. Never
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Angle a = 126. What is the measure of angle b? Explain how you calculated your answer.

Angle a = 126 Write an equation(s) in terms of b to find the measure of angle h.

Calculate the measure of angle h, using the equation(s) you wrote for Part B.

How would knowing the measure of angle y change the equation(s) you wrote in Part B to find the measure of angle h?

2021 Muminate Education Inc Your input: factor x2+4x+3.

To factor the quadratic function x2+4x+3, we should solve the corresponding quadratic equation x2+4x+3=0.

Indeed, if x1 and x2 are the roots of the quadratic equation ax2+bx+c=0, then ax2+bx+c=a(x−x1)(x−x2).

Solve the quadratic equation x2+4x+3=0.

The roots are x1=−1, x2=−3 (use the quadratic equation calculator to see the steps).

Therefore, x2+4x+3=1(x+1)(x+3).

(x2+4x+3)=1(x+1)(x+3)

Step-by-step explanation:

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3 years ago
What is the domain of the function y = 2 StartRoot x minus 5 EndRoot?
Juli2301 [7.4K]

Answer:

The domain of the function should be:

'x greater than or equal to negative -5'.

Hence, option A is true.

Step-by-step explanation:

Given the expression

2\sqrt{x-5}

The domain of a function is the set of input or arguments for which the function is real and defined

We know that the value, inside the radicand, is the number found inside a radical symbol which must be greater than 0, otherwise, it would make the function undefined,

i.e.

x-5 ≥ 0

x ≥ 5

In other words, the domain of the function should be:

'x greater than or equal to negative -5'.

Therefore, the domain of the function:

x ≥ 5

\mathrm{Domain\:of\:}\:2\sqrt{x-5}\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\ge \:5\:\\ \:\mathrm{Interval\:Notation:}&\:[5,\:\infty \:)\end{bmatrix}

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