Answer:
okb-joye-ngv
C O m e t o l e a r n s e x
or m a k e s e x
Given:
The equation is:
![3^x\times 9=3^{2n-1}](https://tex.z-dn.net/?f=3%5Ex%5Ctimes%209%3D3%5E%7B2n-1%7D)
To find:
The value of n in terms of x.
Solution:
We have,
![3^x\times 9=3^{2n-1}](https://tex.z-dn.net/?f=3%5Ex%5Ctimes%209%3D3%5E%7B2n-1%7D)
It can be written as
![3^x\times 3^2=3^{2n-1}](https://tex.z-dn.net/?f=3%5Ex%5Ctimes%203%5E2%3D3%5E%7B2n-1%7D)
![[\because a^ma^n=a^{m+n}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5Ema%5En%3Da%5E%7Bm%2Bn%7D%5D)
On comparing the exponents, we get
![x+2=2n-1](https://tex.z-dn.net/?f=x%2B2%3D2n-1)
Add 1 on both sides.
![x+2+1=2n-1+1](https://tex.z-dn.net/?f=x%2B2%2B1%3D2n-1%2B1)
![x+3=2n](https://tex.z-dn.net/?f=x%2B3%3D2n)
Divide both sides by 2.
![\dfrac{x+3}{2}=n](https://tex.z-dn.net/?f=%5Cdfrac%7Bx%2B3%7D%7B2%7D%3Dn)
Therefore, the value of n is terms of x is
.
I'll assume those are squares. We know D is an identity:
![\sin^2 x + \cos ^2 x = 1](https://tex.z-dn.net/?f=%5Csin%5E2%20x%20%2B%20%5Ccos%20%5E2%20x%20%3D%201)
Dividing through by
![\sin ^2 x](https://tex.z-dn.net/?f=%5Csin%20%5E2%20x)
![1 + \cot^2 x = \csc^2 x](https://tex.z-dn.net/?f=1%20%2B%20%5Ccot%5E2%20x%20%3D%20%5Ccsc%5E2%20x)
That's A.
Dividing the original through by
![\cos ^2 x](https://tex.z-dn.net/?f=%5Ccos%20%5E2%20x)
![\tan^2 x + 1 = \sec^2 x](https://tex.z-dn.net/?f=%5Ctan%5E2%20x%20%2B%201%20%3D%20%5Csec%5E2%20x)
Not quite B, wrong sign on tangent.
C has the wrong sign on cosine squared as well.
Identities: A & D
The expression that represents Lonnie's final number is 2(x + 3) - 6
<h3>Writing an expression</h3>
From the given information, we are to write the expression that represents Lonnie's final number
From the given information,
"<em>kristy asks lonnie to think of a number, add 3 to it</em>"
Let the number be x
Then,
The statement becomes
x + 3
<em>"multiply the sum by 2</em>" we get
2×(x +3)
= 2(x + 3)
"<em> subtract 6</em>",
The expression becomes
2(x + 3) - 6
This is the expression that represents Lonnie's final number
Hence, the expression that represents Lonnie's final number is 2(x + 3) - 6
Learn more on Writing an expression here: brainly.com/question/12166019
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Answer:
13x+8
Step-by-step explanation:
9(4x-3) -23x+35
36x-27-23x+35
13x+8