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Sveta_85 [38]
3 years ago
11

Function Q gives a puppy's weight in pounds as function of its age in months. What does each expression represent in this situat

ion. Q(18) Q(30) = 27.5
Mathematics
1 answer:
babymother [125]3 years ago
6 0

Answer:

Q(18) is a mathematical representation of the weight in pounds of a puppy after 18 months.

Q(30) = 27.5 ; This means that the weight of puppy after 30 months will be 27.5 pounds

Step-by-step explanation:

Given the expressions :

Q(18)

Q(30) = 27.5

Function Q gives a puppy's weight in pounds as function of its age in months

What does each expression represent in this situation?

A function is generally represented in the form a(x) ;

Hence, Q(18) is a mathematical representation of the weight in pounds of a puppy after 17 months

Q(30) = 27.5 ; This means that the weight of puppy after 30 months will be 27.5 pounds. 27.5 is the result of working out the function Q at 30.

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A pet store conducted a survey on the types of pets owned by the stores customers. construct a two-way table summarizing the dat
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Answer:

\begin{array}{cccc}&\text{Own cat}&\text{Do not own cat}&\text{Total}\\\text{Own dog}& 45 & 125 & 170\\\text{Do not own dog}& 78 & 52 & 130 \\\text{Total}& 123 & 177 &300\end{array}

Step-by-step explanation:

From the table you can see that

  • 45 customers own cat and dog;
  • 78 own only cat, then 78+45=123 customers own cat;
  • 125 own only dog, then 125+45=170 customers own dog;
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Two-way table is

\begin{array}{cccc}&\text{Own cat}&\text{Do not own cat}&\text{Total}\\\text{Own dog}& 45 & 125 & 170\\\text{Do not own dog}& 78 & 52 & 130 \\\text{Total}& 123 & 177 &300\end{array}

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3 years ago
The combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 m
rewona [7]

Answer:

Approximately 50 pounds less carbon (in CO₂) will be produced by the second auto on this trip.

Step-by-step explanation:

We have been given that the combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 miles.

Let us find amount of fuel used by autos by dividing the total distance by their mileage.

\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\frac{\text{ 20 miles}}{\text{gallon}}}

\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\text{ 20 miles}}\times \text{gallon}

\text{Fuel used by 1st auto}=30 \text{ gallons}

\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\frac{\text{ 30 miles}}{\text{gallon}}}

\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\text{ 30 miles}}\times \text{gallon}

\text{Fuel used by 2nd auto}=20 \text{ gallons}

Let us find the difference of fuel used by both autos.

\text{Number of gallons that 2nd auto used less than 1st auto}=30-20

\text{Number of gallons that 2nd auto used less than 1st auto}=10

Since one gallon of automobile fuel produces about 5 pounds of carbon, so 10 gallons of fuel will produces 5\times 10=50 pounds of carbon.

Since 2nd auto used 10 gallons less than 1st auto, therefore, 2nd auto will produce 50 pounds less carbon than 1st auto.

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3 years ago
If f(x)=3x and g(x)=1/x what is the domain of (gof)(x)?
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