Bill spent 2/3 of an hour swimming and 5/6 of an hour jogging. How much longer did he jog than swim
2 answers:
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Answer:
c = 4.79 feet
Step-by-step explanation:
Given question is incomplete without a picture; find the question with the attachment.
Two poles AD and DB of same length are leaning against each other.
Distance between the poles (AB) = 45 feet
m(∠ADB) = 180°- (60 + 50)°
= 70°
By sine rule,
= 36.68 ft
Similarly,
DB =
= 41.47 ft
Now c = DB - AD
= 41.47 - 36.68
= 4.79 feet
