To find a number in between you could multiply 39/130 by 2/2
and 40/130 by 2/2 to get
78/260 and 80/260
Answer:
Step-by-step explanation:
a1 = 6
a2 = 10
a3 = 14
The next member of the sequence is 4 more than the current sequence. Therefore d = 4
a1 = 6
d = 4
n = 13
an = a1 + (n - 1)*d
an = 6 + (n - 1)*4
a_13 = 6 + 12*4
a_13 = 6 + 48
a_13 = 54
Answer:
84
Step-by-step explanation:
f(x) = 3x^2 + 2x – 1
Let x=5
f(5) = 3(5)^2+2(5) -1
= 3*25 +10-1
= 75+10 -1
= 85 -1
Part 1
<h3>Answer: 13</h3>
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Explanation:
We'll replace every copy of x with -3. Then use PEMDAS to simplify.
f(x) = -2x+7
f(-3) = -2(-3)+7
f(-3) = 6+7
f(-3) = 13
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Part 2
<h3>Answer: -11</h3>
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Explanation:
We work backwards in a sense compared to what part 1 did. Instead of finding f(x) based on x, we determine what x must be for a given f(x).
We'll replace f(x) with 29 and solve for x like so
f(x) = -2x+7
29 = -2x+7
-2x+7 = 29
-2x = 29-7
-2x = 22
x = 22/(-2)
x = -11
Note how if you replaced x with -11, we'd get,
f(x) = -2x+7
f(-11) = -2(-11)+7
f(-11) = 22+7
f(-11) = 29
which helps confirm we have the correct answer.
Given
Rob is twice Joshua's age
Nick is 5 years older than Joshua.
sum of all their ages is 45.
Find the age of nick.
To proof
As given
Rob is twice Joshua's age
let Joshua's age = x
than Rob age = 2x
Nick is 5 years older than Joshua.
Nick age = 5 + x
sum of all their ages is 45
than the equation becomes
Joshua's age + Rob age + Nick age = 45
put the value
x + 2x + 5 + x = 45
4x = 40
x = 10
Joshua's age = 10 year
than Rob age = 20 year
Nick age = 5 + 10
= 15year
Hence proved
