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Artist 52 [7]
3 years ago
8

In a triangle ABC, D and E are the mid points of AB and AC respectively. If DE|| BC and

Mathematics
1 answer:
Illusion [34]3 years ago
6 0

Answer:

DE = 5 cm

Step-by-step explanation:

Using the midline theorem.

A segment joining the midpoints of 2 sides of a triangle DE and parallel to the third side BC is one half the length of the third side, that is

DE = 0.5BC = 0.5 × 10 = 5

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1/5 = 2/10


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Goran ran three times last week. Here are the distances he ran (in kilometers).9.94,6.65,10 What is the total distance Goran ran
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7 0
3 years ago
A piece of cardboard measures 10 ft by 10 ft. Four equal squares of size x are removed from the corners. After removing the squa
Gnesinka [82]

Answer:

The value of x would be \frac{5}{3}

Step-by-step explanation:

Given,

The dimension of the cardboard = 10 ft by 10 ft,

∵ After removing four equal squares of size x ( in ft ) from the corners,

The dimension of the resultant box would be,

Length = ( 10 - 2x ) ft,

Width = ( 10 - 2x ) ft,

Height = x ft,

The volume of box,

V=(10-2x)\times (10 - 2x)\times x=x(10-2x)^2 = x(100 - 40x + 4x^2)=100x - 40x^2 + 4x^3

Differentiating with respect to x,

V'=100 - 80x + 12x^2

Again differentiating with respect to x,

V''=-80 + 24x

For maxima or minima,

V'=0

\implies 100 - 80x + 12x^2 = 0

\implies 3x^2 - 20x + 25=0

By quadratic formula,

x=\frac{20\pm \sqrt{20^2-4\times 3\times 25}}{6}

x=\frac{20\pm \sqrt{400 - 300}}{6}

x=\frac{20\pm \sqrt{100}}{6}

x=\frac{20\pm 10}{6}

\implies x = \frac{10}{6}=\frac{5}{3}\text{ or } x = 5

For x = 5/3, V'' = negative,

While for x = 5, V'' = Positive,

Hence, the value of x would be 5/3 ft for maximising the volume.

8 0
3 years ago
PLEASE HELP ME FAST!!!!
poizon [28]
The answer is going to be A
3 0
3 years ago
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