Answer:
L = (P - 2W)/2
Step-by-step explanation:
This is the formula for perimeter
P = 2L + 2W
Sustract 2W on both sides:
P-2W= 2L
Divide both sides by 2:
(P-2W)/2 = L
L= (P-2W)/2
Answer:
20, 4
Step-by-step explanation:
Let's assume total number of students registered is n
Last week n/4 people are absent
so people present are n - n/4 = <u>3n/4</u>
Today after return of Jen 1/5 n are absent
so people present are n - n/5 = 4n/5
which is also equal to last week present people + 1 (Jen)
= 3n/4 + 1
= (3n + 4) / 4
so (3n + 4) / 4 = 4n/5
=> 3n + 4 = 4n/5 * 4
=> (3n + 4) * 5 = 16n
=> 15n + 20 = 16n
=> 20 = n
=> n = 20
So total students registered for class is 20
today no of people absent = n/5 = 20/5 = 4
Answer:
Yes, the shapes are similar. Note, the angles are equivalent and the sides are scales of each other satisfying the requirements for similarly.
Step-by-step explanation:
For a shape to be similar there are two conditions that must be met. (1) Must have equivalent angles (2) Sides must be related by a scalar.
In the two triangles presented, the first condition is met since each triangle has three angles, 90-53-37.
To test if the sides are scalar, each side must be related to a corresponding side of the other triangle with the same scalar.
9/6 = 3/2
12/8 = 3/2
15/10 = 3/2
Alternatively:
6/9 = 2/3
8/12 = 2/3
10/15 = 2/3
Since the relationship of the sides is the scalar 3/2 (Alternatively 2/3), then we can say the triangles meet the second condition.
Given that both conditions are satisfied, then we can say these triangles are similar.
Note, this is a "special case" right triangle commonly referred to as a 3-4-5 right triangle.
Cheers.
Answer:
The answer is -6 but its not in the option
Step-by-step explanation:
Let x = -5
[(-5)²-1]/(-5+1)
= (25-1)/(-4)
= 24/-4
= -6
