Hi sis I’m gonna stop calling me and
The answer will be 132 because if you add it thats what you will get
Answer:
The answer to the question is
If Boston is at D and C is 90 km away from Boston, then the two cars will meet at 30 km from Boston.
Step-by-step explanation:
Let the speed of the car that start from C = V₁
Let the speed of the car that start from D = V₂
Therefore where V₁ = 2·V₂
We have at time t when the cars meet the distance covered by the car that start from C will be V₁×t = 2·V₂×t, while the distance of the other car will be
V₂×t
Which means that the distance covered by the car that start from C is twice that of the car that start from D
Hence if Boston is located at D which is 90 km from C then both cars will meet at
90 km /3 = 30 km from Boston as the car originating from Boston would only have covered 30 km when the two cars meet.
False, since if there are two perpendicular lines with gradients m1 and m2, then m1*m2 = -1.
Taking this example -5/2 multiplied by 5/2 is equal to -25/4, which is not equal to -1.
To find the actual gradient of the perpendicular line you would have to divide -1 by -5/2, which gives you 2/5.
