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Scrat [10]
3 years ago
5

Find the quadratic function y=​f(x) whose graph has a vertex ​(−3​,3​) and passes through the point ​(−6​,0). What is the functi

on in standard form?

Mathematics
1 answer:
adell [148]3 years ago
4 0

Answer:

  f(x) = -1/3x² -2x

Step-by-step explanation:

For vertex (h, k) and scale factor "a", the vertex form of a quadratic is ...

  y = a(x -h)² +k

For the given vertex, the vertex form function with scale factor "a" is ...

  f(x) = a(x +3)² +3

If that goes through the point (-6, 0), then we have ...

  f(-6) = a(-6 +3)² +3 = 0

  9a = -3 . . . . . . . subtract 3

  a = -1/3 . . . . . . . divide by 9

In standard form, the equation is ...

  f(x) = (-1/3)x² -2x

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Use the function shown in the table to answer the questions below .
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Read 2 more answers
I need help 3-6 pleasr
Colt1911 [192]
3) Mathematical expression would be:
 412 - 65 + 0.50x
Where, x = Number of Texts sent

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"Per" tells us the magnitude for an Unit value.

5) Associative property = (a+b) + c = a+ (b+c)
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They all have their unique characteristics and can be differentiated on that basis.

6) They all are same.
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Hope this helps!
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