Answer:
$1800
Step-by-step explanation:
Volume of the foundation: 30*12*6 = 2160 cubic feet
we need to convert this into yards because a truckload is 8 cubic yards, 2160/3 = 720 cubic yd
One truckload is 8 cubic yards
# of truckloads needed: 720/8 = 90 truckloads
Cost: $20*90 = $1800
321 times 23 is 7,383
3,829 divided by 1,221 is (rounded to the nearest hundredth) 3.14
(the real number was: 3.13595414)
Your answer would be 8 Hammond per minute. Hope this helps!
Answer:
The equation of the line is;
y = 3x + 18
Step-by-step explanation:
We want to write the equation of the line through (-9,-9) and (-6,0)
we start by calculating the slope of the line
m = (y2-y1)/(x2-x1) = (0+ 9)/(-6+9) = 9/3 = 3
The general equation of the line is;
y = mx + c
y = 3x + c
To get c, we use any of the points
we substitute for example -6 for x and 0 for y
0 = 3(-6) + c
c = 0 + 18 = 18
So the equation of the line is;
y = 3x + 18
Answer:
You can use either of the following to find "a":
- Pythagorean theorem
- Law of Cosines
Step-by-step explanation:
It looks like you have an isosceles trapezoid with one base 12.6 ft and a height of 15 ft.
I find it reasonably convenient to find the length of x using the sine of the 70° angle:
x = (15 ft)/sin(70°)
x ≈ 15.96 ft
That is not what you asked, but this value is sufficiently different from what is marked on your diagram, that I thought it might be helpful.
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Consider the diagram below. The relation between DE and AE can be written as ...
DE/AE = tan(70°)
AE = DE/tan(70°) = DE·tan(20°)
AE = 15·tan(20°) ≈ 5.459554
Then the length EC is ...
EC = AC - AE
EC = 6.3 - DE·tan(20°) ≈ 0.840446
Now, we can find DC using the Pythagorean theorem:
DC² = DE² + EC²
DC = √(15² +0.840446²) ≈ 15.023527
a ≈ 15.02 ft
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You can also make use of the Law of Cosines and the lengths x=AD and AC to find "a". (Do not round intermediate values from calculations.)
DC² = AD² + AC² - 2·AD·AC·cos(A)
a² = x² +6.3² -2·6.3x·cos(70°) ≈ 225.70635
a = √225.70635 ≈ 15.0235 . . . feet