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3 years ago

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on a map the distance beetween two towns is 2.5 inches and 1 inch represents 6 miles what is the actual distance beetween the to

wns enter your answer in the box

2 answers:

ddd [48]3 years ago

6 0

the math shows itself

6+6+3=15

Alinara [238K]3 years ago

3 0

Answer:

Step-by-step explanation: 13

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1.Encuentra de dos formas diferentes el área de las figuras mostradas en cada literal:

MA_775_DIABLO [31]

Answer:

Cuadrilátero A: $A = y^{2}+4\cdot y +4$

Cuadrilátero B: $A = a^{2}+6\cdot a + 9$

Step-by-step explanation:

Existen dos formas distintas de determinar las áreas de cada cuadrilátero:

(i) <em>Obtener el área de cada cuadrado y sumar los resultados.</em>

(ii) <em>Calcular los lados del cuadrilátero grande y determinar el área. </em>

Cuadrilátero A

Método (i)

$A = y^{2}+2\cdot y +4+2\cdot y$

$A = y^{2}+4\cdot y +4$

Método (ii)

$A = (y+2)\cdot (y+2)$

$A = y^{2}+4\cdot y + 4$

Cuadrilátero B

Método (i)

$A = a^{2}+3\cdot a +9 + 3\cdot a$

$A = a^{2}+6\cdot a +9$

Método (ii)

$A = (a+3)\cdot (a+3)$

$A = a^{2}+6\cdot a + 9$

8 0

2 years ago

Y=-1/3x^2-4x-5 in vertex form

grigory [225]

Answer:

$Y=-\frac{1}{3}(x+6)^2+7$ [Vertex form]

Step-by-step explanation:

Given function:

$Y=-\frac{1}{3}x^2-4x-5$

We need to find the vertex form which is.,

$y=a(x-h)^2+k$

where $(h,k)$ represents the co-ordinates of vertex.

We apply completing square method to do so.

We have

$Y=-\frac{1}{3}x^2-4x-5$

First of all we make sure that the leading co-efficient is =1.

In order to make the leading co-efficient is =1, we multiply each term with -3.

$-3\times Y=-3\times\frac{1}{3}x^2-(-3)\times4x-(-3)\times 5$

$-3Y=x^2+12x+15$

Isolating $x^2$ and $x$ terms on one side.

Subtracting both sides by 15.

$-3Y-15=x^2+12x-15-15$

$-3Y-15=x^2+12x$

In order to make the right side a perfect square trinomial, we will take half of the co-efficient of $x$ term, square it and add it both sides side.

square of half of the co-efficient of $x$ term = $(\frac{1}{2}\times 12)^2=(6)^2=36$

Adding 36 to both sides.

$-3Y-15+36=x^2+12x+36$

$-3Y+21=x^2+12x+36$

Since $x^2+12x+36$ is a perfect square of $(x+6)$ , so, we can write as:

$-3Y+21=(x+6)^2$

Subtracting 21 to both sides:

$-3Y+21-21=(x+6)^2-21$

$-3Y=(x+6)^2-21$

Dividing both sides by -3.

$\frac{-3Y}{-3}=\frac{(x+6)^2}{-3}-\frac{21}{-3}$

$Y=-\frac{1}{3}(x+6)^2+7$ [Vertex form]

8 0

3 years ago

in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference

allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

$\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}$

so that

$a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d$

$a_n=a_1+(n-1)d$

$33=8+(n-1)d$

$21=(n-1)d$

$n$ has to be an integer, which means there are 4 possible cases.

Case 1: $n-1=1$ and $d=21$ . But

$\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123$

Case 2: $n-1=21$ and $d=1$ . But

$\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123$

Case 3: $n-1=3$ and $d=7$ . But

$\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123$

Case 4: $n-1=7$ and $d=3$ . But

$\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123$

8 0

3 years ago

linda is building a rectangular playhouse. the width is x feet. the length is x + 3 the distance around the base of the playhous

Zanzabum

No. The value of x is 7.5 feet.

7 0

3 years ago

The area that lies between Z= - 0.42 and Z= 0.42 is

valentinak56 [21]

Answer:

the answer is 0.84

Step-by-step explanation:

assume the two numbers are on a number line and take the absolute value of their difference

5 0

3 years ago

Read 2 more answers