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Illusion [34]
3 years ago
7

The requirements for TAL Distributors have changed. A number and a name now identify each storehouse. Units of each item may be

stored in multiple storehouses, and it is important to know precisely how many items are stored in each storehouse. In addition, TAL Distributors now wants to manage information about the suppliers from which it purchases items.
For each item, TAL Distributors needs to know the number and name of each supplier as well as the expected lead time for delivering each item. (Lead time is the amount of time a supplier is expected to take to deliver the item after TAL Distributors has ordered it.) Each item can have many suppliers, and each supplier can supply many items.
Using this information, convert the following unnormalized relation to fourth normal form:
Item (ItemNum, Description, Category, Price, (StorehouseNum, StorehouseName, OnHand), (SupplierNum, SupplierName, LeadTime))

Computers and Technology
1 answer:
MrRissso [65]3 years ago
6 0

Answer:

See attachment

Explanation:

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Software that instructs the computer how to run applications and controls the display/keyboard is know as the
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4 years ago
Write a function NumberOfPennies() that returns the total number of pennies given a number of dollars and (optionally) a number
Over [174]

Answer:

Following are the code to the given question:

#include <iostream>//header file  

using namespace std;

int NumberOfPennies(int ND, int NP=0)//defining a method that accepts two parameters  

{

return (ND*100 +NP);//use return keyword that fist multiply by 100 then add the value  

}

int main() //main method

{

cout << NumberOfPennies(5,6) << endl; // Should print 506

cout << NumberOfPennies(4) << endl; // Should print 400

return 0;

}

Output:

506

400

Explanation:

In the method "NumberOfPennies" it accepts two parameters that are "ND and NP" that uses the return keyword that multiply 100 in ND variable and add in NP variable and return its values.

In the main method it it uses the cout method that call the by accepts value in parameter and print its value.

4 0
3 years ago
Two machines can finish a job in StartFraction 20 Over 9 EndFraction hours. Working​ alone, one machine would take one hour long
Alborosie

<em><u>Answer</u></em>

5 hours

<em><u>Explanation</u></em>

The two working together can finish a job in

\frac{20}{9}  \: hours

Also, working alone, one machine would take one hour longer than the other to complete the same job.

Let the slower machine working alone take x hours. Then the faster machine takes x-1 hours to complete the same task working alone.

Their combined rate in terms of x is

\frac{1}{x}    +  \frac{1}{x - 1}

This should be equal to 20/9 hours.

\frac{1}{x}  +  \frac{1}{x - 1}  =  \frac{9}{20}

Multiply through by;

20x(x - 1) \times \frac{1}{x}  +20x(x - 1) \times   \frac{1}{x - 1}  =  20x(x - 1) \times \frac{9}{0}

20(x - 1)  +20x = 9x(x - 1)

20x - 20+20x = 9{x}^{2}  - 9x

9{x}^{2}  - 9x - 20x - 20x + 20= 0

9{x}^{2}  - 49x  + 20= 0

Factor to get:

(9x - 4)(x - 5) = 0

x =  \frac{4}{9}  \: or \: x = 5

It is not feasible for the slower machine to complete the work alone in 4/9 hours if the two will finish in 20/9 hours.

Therefore the slower finish in 5 hours.

8 0
3 years ago
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