f = int(input("Enter a number: "))
if(f%7==0):
print("It's divisible by 7.")
else:
if(f<7):
print("7")
else:
print(str(f-(f%7))+", "+str(f+(7-(f%7))))
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Answer:
In C++:
int PrintInBinary(int num){
if (num == 0)
return 0;
else
return (num % 2 + 10 * PrintInBinary(num / 2));
}
Explanation:
This defines the PrintInBinary function
int PrintInBinary(int num){
This returns 0 is num is 0 or num has been reduced to 0
<em> if (num == 0) </em>
<em> return 0; </em>
If otherwise, see below for further explanation
<em> else
</em>
<em> return (num % 2 + 10 * PrintInBinary(num / 2));
</em>
}
----------------------------------------------------------------------------------------
num % 2 + 10 * PrintInBinary(num / 2)
The above can be split into:
num % 2 and + 10 * PrintInBinary(num / 2)
Assume num is 35.
num % 2 = 1
10 * PrintInBinary(num / 2) => 10 * PrintInBinary(17)
17 will be passed to the function (recursively).
This process will continue until num is 0
Answer: You need a temporary variable to hold the value 3
Explanation:
So, aList[0] is 3 and aList[1] is 19, if it will be as it is you litteraly say to the compiler to change aList[0] to aList[1] at this moment aList[0] is 19 and aList[1] also is 19 and if you try to change aList[1] to aList[0] it will not change its value because they are the same.
You need temp variable to keep one of the values.