Answer:
Given
The above lines of code
Required
Rearrange.
The code is re-arrange d as follows;.
#include<iostream>
int main()
{
int userNum;
scanf("%d", &userNum);
if (userNum > 0)
{
printf("Positive.\n");
}
else
{
printf("Non-positive, converting to 1.\n");
userNum = 1;
printf("Final: %d\n", userNum);
}
return 0;
}
When rearranging lines of codes. one has to be mindful of the programming language, the syntax of the language and control structures in the code;
One should take note of the variable declarations and usage
See attachment for .cpp file
Answer:
IN MY PROFILE
Explanation:
I HAVE AWNSERED THIS QUESTION THROUGHOUT MY BEING HERE PLEASE DO NOT BE AFRAID TO CLICK ON MY PROFILE AND FIND THE ANSWER
Answer:
Number 2 Polygonal lasso tool
Explanation:
