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3 years ago

How do you do x intercept

Mathematics

2 answers:

Brums [2.3K]3 years ago

8 0

Answer:

Find where the point hits the X- axis

Step-by-step explanation:

When looking at a graph, there is an X and Y- axis. To find the X- intercept you look where the point hits the X- axis. This is the same for finding the Y- intercept except instead of the X- axis it's the Y- axis.

antoniya [11.8K]3 years ago

3 0

Sorry in fifth grade

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2 years ago

The Venn diagram shows the results of two events resulting from rolling a number cube.

tankabanditka [31]

Answer:

$P(A|B)=\frac{2}{3}$

$P(A)*P(B)=\frac{1}{3}$

$P(A) =\frac{2}{3}$

$P(B) =\frac{1}{2}$ .

Step-by-step explanation:

We use the Venn diagram to calculate the desired probabilities.

Note that there are 6 possible results in the sample space

S = {1, 2, 3, 4, 5, 6}

Then note that in the region representing the intercept of A and B there are two possible values.

$P (A\ and\ B) = \frac{2}{6} = \frac{1}{3}$

In the region that represents event A there are 4 possible outcomes {4, 5, 1, 2}

$P(A) = \frac{4}{6} = \frac{2}{3}$

In the region that represents event B there are 3 possible outcomes {1, 2, 6}

$P(B) = \frac{3}{6} = \frac{1}{2}$ .

Now

$P(A | B)=\frac{P(A \ and\ B)}{P(B)}\\\\P(A | B)=\frac{\frac{1}{3}}{\frac{1}{2}}\\\\P(A|B)=\frac{2}{3}$

$P(A)*P(B)=\frac{2}{3}*\frac{1}{2}=\frac{1}{3}$

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Read 2 more answers

Suppose two $20 bills, three $10 bills, one $5 bill, and seven $1 bills are placed in a bag. If you were to pull a bill at rando

Korolek [52]

Answer:

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is $\frac{7}{13}$ .

Step-by-step explanation:

From the given question, the bag contains;

$1 bill = 7

$5 bill = 1

$10 bill = 3

$20 bill = 2

Total number of bills in the bag = 13

Pulling a bill at random, the bills would have an expected value as follows:

For $1 bill, the expected value = $\frac{7}{13}$

For $5 bill, expected value = $\frac{1}{13}$

For $10 bill, expected value = $\frac{3}{13}$

For $20 bill, the expected value = $\frac{2}{13}$

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is $\frac{7}{13}$ .

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3 years ago