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Rudik [331]
3 years ago
5

Difference 56,782 and 5,849​

Mathematics
1 answer:
klasskru [66]3 years ago
5 0

-- 56,782 is an even number, whereas 5,849 is an odd number.

-- 56,782 is written with five digits, whereas 5,849 is written with only four.

-- 56,782 is a multiple of 2, 11, and 22, whereas 5,849 has no factor less than 50 (except 1) .

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List your two solutions to help people during a weather-related hazard below:hurricane
irakobra [83]

Answer: Supplies

Step-by-step explanation: the best way to help people is to send them supplies cause usually after a hurricane they could have there home or water source destroyed

7 0
2 years ago
The audio-visual technician for a hotel ordered 4 boxes of microphone cords. There are 12 cords in each box.
Harman [31]
Your equation to solve is 108-(12×4).
This is 108-48 which is 60.
There were 60 cords at the hotel before the order. Since you need to find the boxes you do 60/12 which is 5.
There were 5 boxes.
4 0
3 years ago
Read 2 more answers
a consumer magazine counts the number of tissues per box in a random sample of 15 boxes of No- Rasp facial tissues. The sample s
Alex

Answer:

95% confidence interval for the population variance of the number of tissues per box is [5043.11 , 23401.31].

Step-by-step explanation:

We are given that a consumer magazine counts the number of tissues per box in a random sample of 15 boxes of No- Rasp facial tissues. The sample standard deviation of the number of tissues per box is 97.

Firstly, the pivotal quantity for 95% confidence interval for the population variance is given by;

                         P.Q. = \frac{(n-1)s^{2} }{\sigma^{2} }  ~ \chi^{2}__n_-_1

where, s^{2}  = sample variance = 97^{2} = 9409

              n = sample of boxes = 15

           \sigma^{2}  = population variance

<em>Here for constructing 95% confidence interval we have used chi-square test statistics.</em>

So, 95% confidence interval for the population variance, \sigma^{2} is ;

P(5.629 < \chi^{2}__1_4 < 26.12) = 0.95  {As the critical value of chi-square at 14

                                         degree of freedom are 5.629 & 26.12}  

P(5.629 < \frac{(n-1)s^{2} }{\sigma^{2} } < 26.12) = 0.95

P( \frac{5.629 }{(n-1)s^{2} } < \frac{1}{\sigma^{2} } < \frac{26.12 }{(n-1)s^{2} } ) = 0.95

P( \frac{(n-1)s^{2} }{26.12 } < \sigma^{2} < \frac{(n-1)s^{2} }{5.629 } ) = 0.95

<u><em>95% confidence interval for</em></u> \sigma^{2} = [ \frac{(n-1)s^{2} }{26.12 } , \frac{(n-1)s^{2} }{5.629 } ]

                                                  = [ \frac{14 \times 9409 }{26.12 } , \frac{14 \times 9409 }{5.629 } ]

                                                  = [5043.11 , 23401.31]

Therefore, 95% confidence interval for the population variance of the number of tissues per box is [5043.11 , 23401.31].

6 0
3 years ago
Three friends earned more than $197 washing cars. They paid their parents $28 for supplies and then divided the rest of the mone
Umnica [9.8K]

Answer:

x>169/3

Step-by-step explanation:

x- the money that each earned

3x>197-28

3x>169

x>169/3

6 0
3 years ago
HELP ME PLEASE!!!!!!!
kotegsom [21]

Answer:

1. (0,0) (3,1) (6,2)

2. proportinal

3. im so sorry but i cant see that one i really am sorry!

Step-by-step explanation:

i hope i helped brainliest?

3 0
3 years ago
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